Solve this following
Question: $0.01$ moles of a weak acid $\mathrm{HA}\left(\mathrm{K}_{\mathrm{a}}=2.0 \times 10^{-6}\right)$ is dissolved in $1.0 \mathrm{~L}$ of $0.1 \mathrm{M} \mathrm{HCl}$ solution. The degree of dissociation of HA is $\times 10^{-5}$ (Round off to the Nearest Integer). [Neglect volume change on adding HA. Assume degree of dissociation $1$ ] Solution: $\mathrm{HA} \rightleftharpoons \mathrm{H}^{+}+\mathrm{A}^{-}$ Initial conc. $0.01 \mathrm{M} \quad 0.1 \mathrm{M} \quad 0$ Equ. conc. $(0.01-\m...
Read More →Match List-I with List-II
Question: Match List-I with List-II Choose the most appropriate answer from the options given below:a-i, b-iv, c-iii, d-iia-iii, b-ii, c-iv, d-ia-iii, b-iv, c-ii, d-ia-iii, b-ii, c-i, d-ivCorrect Option: , 3 Solution: $\mathrm{Ca}(\mathrm{OCl})_{2}$ is Bleach. $\mathrm{CaSO}_{4} \cdot \frac{1}{2} \mathrm{H}_{2} \mathrm{O}$ is plaster of paris. $\mathrm{CaCO}_{3}$ is used as an antacid. $\mathrm{CaO}$ is major component of cement....
Read More →The reaction of white phosphorus on boiling with alkali in inert atmosphere resulted in the formation of product
Question: The reaction of white phosphorus on boiling with alkali in inert atmosphere resulted in the formation of product 'A'. The reaction $1 \mathrm{~mol}$ of 'A' with excess of $\mathrm{AgNO}_{3}$ in aqueous medium gives $\mathrm{mol}(\mathrm{s})$ of $\mathrm{Ag}$. (Round off to the Nearest Integer). Solution: $\mathrm{P}_{4}+3 \mathrm{OH}^{-}+3 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{PH}_{3}+\underset{(\mathrm{A})}{3 \mathrm{H}_{2} \mathrm{PO}_{2}^{-}}$ $\underset{1 \text { mole }}{\m...
Read More →A group 15 element, which is a metal and forms a hydride with strongest reducing power among group 15 hydrides. The element is :
Question: A group 15 element, which is a metal and forms a hydride with strongest reducing power among group 15 hydrides. The element is :SbpAsBiCorrect Option: , 4 Solution: In group 15 $\left.\begin{array}{l}\mathrm{N} \\ \mathrm{P}\end{array}\right] \rightarrow$ Non metal $\left.\begin{array}{l}\text { As } \\ \text { Sb }\end{array}\right] \rightarrow$ Metalloid $\mathrm{Bi}] \rightarrow$ Metal Hydrides of group 15 elements are $\mathrm{NH}_{3}$ $\mathrm{PH}_{3}$ $\mathrm{AsH}_{3}$ $\mathrm{...
Read More →The point of intersection and sudden increase in the slope, in the diagram given below, respectively, indicates:
Question: The point of intersection and sudden increase in the slope, in the diagram given below, respectively, indicates: $\Delta \mathrm{G}=0$ and melting or boiling point of the metal oxide$\Delta \mathrm{G}0$ and decomposition of the metal oxide$\Delta \mathrm{G}0$ and decomposition of the metal oxide$\Delta \mathrm{G}=0$ and reduction of the metal oxideCorrect Option: 1 Solution: At intersection point $\Delta \mathrm{G}=0$ and sudden increase in slope is due to melting or boiling point of t...
Read More →The satements that are TRUE :
Question: The satements that are TRUE : (A) Methane leads to both global warming and photochemical smog (B) Methane is generated from paddy fields (C) Methane is a stronger global warming gas than $\mathrm{CO}_{2}$ (D) Methane is a part of reducing smog Choose the most appropriate answer from the options given below:(A), (B), (C) only(A) and (B) only(B), (C), (D) only(A), (B), (D) onlyCorrect Option: 1 Solution: Methane leads to both global warming \ photochemical smog. Methane is generated in l...
Read More →The solubility product of PbI_2 is 8.0 × 10^-9.
Question: The solubility product of $\mathrm{PbI}_{2}$ is $8.0 \times 10^{-9}$. The solubility of lead iodide in $0.1$ molar solution of lead nitrate is $x \times 10^{-6} \mathrm{~mol} / \mathrm{L}$. The value of $x$ is . (Rounded off to the nearest integer) $[$ Given $: \sqrt{2}=1.41]$ Solution: Given : $\left[\mathrm{K}_{\mathrm{sp}}\right]_{\mathrm{PbI}_{2}}=8 \times 10^{-9}$ To calculate : solubility of $\mathrm{PbI}_{2}$ in $0.1 \mathrm{M}$ sol of $\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2...
Read More →Match List-I with List-II :
Question: Match List-I with List-II : (Chemicals) (a) Alcoholic potassium hydroxide (b) $\mathrm{Pd} / \mathrm{BaSO}_{4}$ (c) $\mathrm{BHC}$ (Benzene hexachloride) (d) Polyacetylene List-II (Use / Preparation / Constituent) (i) Electrodes in batteries (ii) Obtained by addition reaction (iii) Used for $\beta$ - elimination reaction (iv) Lindlar's catalyst Choose the most appropriate match :a-ii, b-i, c-iv, d-iiia-iii, b-iv, c-ii, d-ia-iii, b-i, c-iv, d-iia-ii, b-iv, c-i, d-iiiCorrect Option: , 2 ...
Read More →Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R :
Question: Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R : Assertion A : The H-O-H bond angle in water molecule is $104.5^{\circ}$. Reason $\mathbf{R}$ : The lone pair - lone pair repulsion of electrons is higher than the bond pair - bond pair repulsion.A is false but R is trueBoth A and R are true, but R is not the correct correct explanation of AA is true but R is falseBoth A and R are true, and R is the correct explanation of ACorrect Opt...
Read More →What is the spin-only magnetic moment value (BM) of a divalent metal ion with atomic number 25 , in it's aqueous solution?
Question: What is the spin-only magnetic moment value (BM) of a divalent metal ion with atomic number 25 , in it's aqueous solution? $5.92$$5.0$zero$5.26$Correct Option: 1 Solution: Electronic configuration of divalent metal ion having atomic number 25 is Total number of unpaired electrons $=5$ $\mu$ (Magnetic moment) $=\sqrt{\mathrm{n}(\mathrm{n}+2)}$ BM where $n=$ number of unpaired $e^{-}$ $\therefore \mu=\sqrt{5(5+2)}=\sqrt{35} \mathrm{BM}=5.92 \mathrm{BM}$...
Read More →The magnitude of the change in oxidising power of the
Question: The magnitude of the change in oxidising power of the $\mathrm{MnO}_{4}^{-} / \mathrm{Mn}^{2+}$ couple is $\mathrm{x} \times 10^{-4} \mathrm{~V}$, if the $\mathrm{H}^{+}$concentration is decreased from $1 \mathrm{M}$ to $10^{-4} \mathrm{M}$ at $25^{\circ} \mathrm{C}$. (Assume concentration of $\mathrm{MnO}_{4}^{-}$and $\mathrm{Mn}^{2+}$ to be same on change in $\mathrm{H}^{+}$ concentration). The value of $x$ is (Rounded off to the nearest integer) $\left[\right.$ Given $\left.: \frac{...
Read More →The correct order of conductivity of ions in water is :
Question: The correct order of conductivity of ions in water is : $\mathrm{Na}^{+}\mathrm{K}^{+}\mathrm{Rb}^{+}\mathrm{Cs}^{+}$$\mathrm{Cs}^{+}\mathrm{Rb}^{+}\mathrm{K}^{+}\mathrm{Na}^{+}$$\mathrm{K}^{+}\mathrm{Na}^{+}\mathrm{Cs}^{+}\mathrm{Rb}^{+}$$\mathrm{Rb}^{+}\mathrm{Na}^{+}\mathrm{K}^{+}\mathrm{Li}^{+}$Correct Option: , 2 Solution: As the size of gaseous ion decreases, it get more hydrated in water and hence, the size of aqueous ion increases. When this bulky ion move in solution, it exper...
Read More →Match List-I with List-II :
Question: Match List-I with List-II : Choose the correct answer from the options given below :(a)-(v), (b)-(i), (c)-(ii), (d)-(iii)(a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)(a)-(iv), (b)-(v), (c)-(ii), (d)-(iii)(a)-(v), (b)-(iv), (c)-(ii), (d)-(iii)Correct Option: Solution: (a) Hypophosphorus acid : $\mathrm{H}_{3} \mathrm{PO}_{2}$ $(+1) 3+x+(-2) 2=0$ $x=+1$ (b) Orthophosphoric acid: $\mathrm{H}_{3} \mathrm{PO}_{4}$ $(+1) 3+x+(-2) 4=0$ $x=+5$ (c) Hypophosphoric acid: $\mathrm{H}_{4} \mathrm{P}_{2} \...
Read More →C_6H_6 freezes at 5.5°circ C. The temperature at which
Question: $\mathrm{C}_{6} \mathrm{H}_{6}$ freezes at $5.5^{\circ} \mathrm{C}$. The temperature at which a solution $10 \mathrm{~g}$ of $\mathrm{C}_{4} \mathrm{H}_{10}$ in $200 \mathrm{~g}$ of $\mathrm{C}_{6} \mathrm{H}_{6}$ freeze is ${ }^{\circ} \mathrm{C}$. (The molal freezing point depression constant of $\mathrm{C}_{6} \mathrm{H}_{6}$ is $5.12^{\circ} \mathrm{C} / \mathrm{m}$.) Solution: Pure Solvent : $\mathrm{C}_{6} \mathrm{H}_{6}(\ell)$ Given : $\mathrm{T}_{\mathrm{f}}^{\circ}=5.5^{\circ}...
Read More →The INCORRECT statement(s) about heavy water is (are)
Question: The INCORRECT statement(s) about heavy water is (are) (A) used as a moderator in nuclear reactor (B) obtained as a by-product in fertilizer industry. (C) used for the study of reaction mechanism (D) has a higher dielectric constant than water Choose the correct answer from the options given below: (B) only(C) only(D) only(B) and (D) onlyCorrect Option: , 3 Solution: The dielectric constant of $\mathrm{H}_{2} \mathrm{O}$ is greater than heavy water....
Read More →A colloidal system consisting of a gas dispersed in a solid is called a/an :
Question: A colloidal system consisting of a gas dispersed in a solid is called a/an :solid solgelaerosolfoamCorrect Option: 1 Solution: Colloid of gas dispersed in solid is called solid sol....
Read More →The process that involves the removal of sulphur from the ores is :
Question: The process that involves the removal of sulphur from the ores is :SmeltingRoastingLeachingRefiningCorrect Option: , 2 Solution: In roasting process, metal sulphide (MS) ore are converted into metal oxide and sulphur is remove in the form of $\mathrm{SO}_{2}$ gas. $2 \mathrm{MS}+3 \mathrm{O}_{2} \stackrel{\Delta}{\longrightarrow} 2 \mathrm{MO}+2 \mathrm{SO}_{2} \uparrow$...
Read More →Which of the following reaction DOES NOT involve Hoffmann Bromamide degradation ?
Question: Which of the following reaction DOES NOT involve Hoffmann Bromamide degradation ?Correct Option: Solution: $\Rightarrow$ This reaction does not involve haffmann bromanide degradation. $\Rightarrow \quad$ Rest all options involve haffmann bromamide degradation during the reaction of $\mathrm{Br}_{2}+\mathrm{NaOH}$ with amide....
Read More →Which of the following reaction is an example of ammonolysis?
Question: Which of the following reaction is an example of ammonolysis?$\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COCl}+\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2} \longrightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CONHC}_{6} \mathrm{H}_{5}$$\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{CN} \stackrel{[\mathrm{H}]}{\longrightarrow} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}$$\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2} \stackrel{\mathrm{HCl}}{\longrigh...
Read More →The volume occupied by 4.75 g of acetylene gas
Question: The volume occupied by $4.75 \mathrm{~g}$ of acetylene gas at $50^{\circ} \mathrm{C}$ and $740 \mathrm{mmHg}$ pressure is (Rounded off to the nearest integer) $\left[\right.$ Given $\mathrm{R}=0.0826 \mathrm{~L}$ atm $\left.\mathrm{K}^{-1} \mathrm{~mol}^{-1}\right]$ Solution: Given Mass $=4.75 \mathrm{~g} \Rightarrow \mathrm{C}_{2} \mathrm{H}_{2}(\mathrm{~g})$ $\Rightarrow$ Moles $=\frac{4.75}{26} \mathrm{~mol}$ $\mathrm{Temp}=50+273=323 \mathrm{~K}$ $\mathrm{P}=\frac{740}{760} \mathrm...
Read More →Match List-I with List-II
Question: Match List-I with List-II Choose the most appropriate answer from the options given below :a-iii,b-ii, c-iv, d-ia-iv, b-iii, c-ii, d-i$\mathrm{a}-\mathrm{iv}, \mathrm{b}-\mathrm{iii}, \mathrm{c}-\mathrm{i}, \mathrm{d}-\mathrm{ii}$a-iv, b-ii, c-iii, d-iCorrect Option: , 2 Solution: Chlorophyll is a coordination compound of magnesium. Vitamin B-12, cyanocobalamine is a coordination compound of cobalt. Cisplatin is used as an anti-cancer drug and is a coordination compound of platinum. Gr...
Read More →The formula of a gaseous hydrocarbon which requires 6 times
Question: The formula of a gaseous hydrocarbon which requires 6 times of its own volume of $\mathrm{O}_{2}$ for complete oxidation and produces 4 times its own volume of $\mathrm{CO}_{2}$ is $\mathrm{C}_{\mathrm{x}} \mathrm{H}_{\mathrm{y}}$. The value of $\mathrm{y}$ is Solution: Combustion $\mathrm{rx}^{\mathrm{n}}$ : $\mathrm{C}_{\mathrm{x}} \mathrm{H}_{\mathrm{y}(\mathrm{g})}+\left(\mathrm{x}+\frac{\mathrm{y}}{4}\right) \mathrm{O}_{2}(\mathrm{~g}) \rightarrow \mathrm{x} \mathrm{CO}_{2}(\mathr...
Read More →Prove the following
Question: Consider the above chemical reaction and identify product "A"Correct Option: , 3 Solution:...
Read More →Among the following allotropic forms of sulphur,
Question: Among the following allotropic forms of sulphur, the number of allotropic forms, which will show paramagnetism is (A) $\alpha$-sulphur (B) $\beta$-sulphur (C) $S_{2}$-form Solution: $\alpha$-sulphur and $\beta$-sulphur are diamagnetic. $\mathrm{S}_{2}$-form is paramagnetic....
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