What is the spin-only magnetic moment value (BM) of a divalent metal ion with atomic number 25 , in it's aqueous solution?

Electronic configuration of divalent metal ion having atomic number 25 is

Total number of unpaired electrons $=5$

$\mu$ (Magnetic moment) $=\sqrt{\mathrm{n}(\mathrm{n}+2)}$ BM

where $n=$ number of unpaired $e^{-}$

$\therefore \mu=\sqrt{5(5+2)}=\sqrt{35} \mathrm{BM}=5.92 \mathrm{BM}$