The reaction of white phosphorus on boiling with alkali in inert atmosphere resulted in the formation of product
Question:
The reaction of white phosphorus on boiling with alkali in inert atmosphere resulted in the formation of product 'A'. The reaction $1 \mathrm{~mol}$ of 'A' with excess of $\mathrm{AgNO}_{3}$ in aqueous medium gives $\mathrm{mol}(\mathrm{s})$ of $\mathrm{Ag}$. (Round off to the Nearest Integer).
Solution:
$\mathrm{P}_{4}+3 \mathrm{OH}^{-}+3 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{PH}_{3}+\underset{(\mathrm{A})}{3 \mathrm{H}_{2} \mathrm{PO}_{2}^{-}}$
$\underset{1 \text { mole }}{\mathrm{H}_{2} \mathrm{PO}_{2}^{-}}+\underset{\text { excess }}{4 \mathrm{Ag}^{+}}+2 \mathrm{H}_{2} \mathrm{O} \rightarrow \underset{4 \text { mole }}{4 \mathrm{Ag}+\mathrm{H}_{3} \mathrm{PO}_{4}}+3 \mathrm{H}^{+}$