The reaction of white phosphorus on boiling with alkali in inert atmosphere resulted in the formation of product
The reaction of white phosphorus on boiling with alkali in inert atmosphere resulted in the formation of product 'A'. The reaction $1 \mathrm{~mol}$ of 'A' with excess of $\mathrm{AgNO}_{3}$ in aqueous medium gives $\mathrm{mol}(\mathrm{s})$ of $\mathrm{Ag}$. (Round off to the Nearest Integer).
$\mathrm{P}_{4}+3 \mathrm{OH}^{-}+3 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{PH}_{3}+\underset{(\mathrm{A})}{3 \mathrm{H}_{2} \mathrm{PO}_{2}^{-}}$
$\underset{1 \text { mole }}{\mathrm{H}_{2} \mathrm{PO}_{2}^{-}}+\underset{\text { excess }}{4 \mathrm{Ag}^{+}}+2 \mathrm{H}_{2} \mathrm{O} \rightarrow \underset{4 \text { mole }}{4 \mathrm{Ag}+\mathrm{H}_{3} \mathrm{PO}_{4}}+3 \mathrm{H}^{+}$
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