Match the complex ions given in Column
Question: Match the complex ions given in Column I with the colours given in Column II and assign the correct code : Code : (i) A (1) B (2) C (4) D (5) (ii) A (4) B (3) C (2) D (1) (iii) A (3) B (2) C (4) D (1) (iv) A (4) B (1) C (2) D (3) Solution: Option (ii) is the answer....
Read More →Name the type of isomerism when ambidentate ligands
Question: Name the type of isomerism when ambidentate ligands are attached to a central metal ion. Give two examples of ambidentate ligands. Solution: Ambidendate ligands are those having different two binding sites. Examples: Isothiocyanato Thiocyanato and Nitrite-N Nitrito-O The type of isomerism when ambidentate ligands are attached to a central metal ion is called linkage isomerism because they only differ in the atom that is linked to the central metal ion....
Read More →CuSO4.5H2O is blue
Question: CuSO4.5H2O is blue while CuSO4 is colourless. Why? Solution: In CuSO4.5H2O, there are water molecules that act as ligands. The electrons will excite to higher d orbital and show colour. Whereas, in CuSO4, there are no water molecules to act as ligands, so no crystal field splitting happens....
Read More →Evaluate the integral:
Question: Evaluate the integral: $\int \sqrt{x^{2}+x+1} d x$ Solution: Key points to solve the problem: - Such problems require the use of the method of substitution along with a method of integration by parts. By the method of integration by parts if we have $\int \mathrm{f}(\mathrm{x}) g(\mathrm{x}) \mathrm{dx}=\mathrm{f}(\mathrm{x}) \int \mathrm{g}(\mathrm{x}) \mathrm{dx}-\int \mathrm{f}^{\prime}(\mathrm{x})\left(\int \mathrm{g}(\mathrm{x}) \mathrm{d} \mathrm{x}\right) \mathrm{dx}$ - To solve...
Read More →Why do compounds having similar geometry
Question: Why do compounds having similar geometry have a different magnetic moment? Solution: They differ in the number of paired and unpaired electrons. A strong field ligand will cause pairing of electrons while a weak field ligand will not cause pairing. Pairing or not pairing will change the number of unpaired electrons, which affects the magnetic moment....
Read More →Arrange following complex ions in increasing
Question: Arrange following complex ions in increasing order of crystal field splitting energy (DO) : [Cr(Cl)6]3, [Cr(CN)6]3, [Cr(NH3)6]3+. Solution: The increasing order of crystal field energy is [Cr(Cl)6]3[Cr(NH3)6]3+ [Cr(CN)6]3 This is also the order of field strength of the ligands according to the spectrochemical series....
Read More →Explain why [Fe(H2O)6]3+ has a magnetic
Question: Explain why [Fe(H2O)6]3+ has a magnetic moment value of 5.92 BM whereas [Fe(CN)6]3 has a value of only 1.74 BM. Solution: For [Fe(H2O)6]3+, H2O is a weak field ligand wont cause pairing of electrons. So, the number of unpaired electrons will be 5. [Fe(CN)6]3, Fe3+ has six unpaired electrons. CN- is a strong field ligand which will cause pairing of all the electrons. So, the electrons will start pairing leaving behind one unpaired electron....
Read More →Why are low spin tetrahedral complexes not formed?
Question: Why are low spin tetrahedral complexes not formed? Solution: For tetrahedral complexes, the crystal field splitting energy is too low. It is lower than pairing energy so, the pairing of electrons is not favoured and therefore the complexes cannot form low spin complexes....
Read More →Based on crystal field theory explain
Question: Based on crystal field theory explain why Co(III) forms a paramagnetic octahedral complex with weak field ligands whereas it forms a diamagnetic octahedral complex with strong field ligands. Solution: The electronic configuration will be t42ge2g.It has 4 unpaired electron and paramagnetic. With weal ligand Δ0 p. The configuration with strong field ligand will be t62ge0g.the Δ0 p and there wont be any unpaired electron therefore diamagnetic....
Read More →The magnetic moment of
Question: The magnetic moment of [MnCl4]2 is 5.92 BM. Explain giving a reason. Solution: A magnetic moment of 5.92 BM means there are 5 unpaired electrons because Magnetic Moment = n(n+2) The geometry tetrahedral with 5 unpaired electrons giving a magnetic moment of 5.92 BM as the four ligands are attached to Mn2+....
Read More →A complex of the type [M(AA)2X2]n+is known
Question: A complex of the type [M(AA)2X2]n+is known to be optically active. What does this indicate about the structure of the complex? Give one example of such complex. Solution: The structure has to be cis-octahedral. Example for such a complex is [Co(en)2Cl2]+ which is optically active....
Read More →A coordination compound CrCl3.4H2O precipitates silver
Question: A coordination compound CrCl3.4H2O precipitates silver chloride when treated with silver nitrate. The molar conductance of its solution corresponds to a total of two ions. Write the structural formula of the compound and name it. Solution: If it forms silver chloride then there is one free chlorine atom outside the coordination sphere. The structural formula has to be [Cr(H2O)4Cl2]Cl. The name of this complex is tetraaquadichlorido chromium(III) chloride....
Read More →Arrange the following complexes in the increasing
Question: Arrange the following complexes in the increasing order of conductivity of their solution: [Co(NH3)3Cl3], [Co(NH3)4Cl2] Cl, [Co(NH3)6]Cl3 , [Cr(NH3)5Cl]Cl2 Solution: The increasing order of conductivity is as follows: [Co(NH3)3Cl3][Co(NH3)4Cl2]Cl [Cr(NH3)5Cl]Cl2[Co(NH3)6]Cl3...
Read More →Evaluate the integral:
Question: Evaluate the integral: $\int \sqrt{3+2 x-x^{2}} d x$ Solution: Key points to solve the problem: - Such problems require the use of method of substitution along with method of integration by parts. By method of integration by parts if we have $\int \mathrm{f}(\mathrm{x}) \mathrm{g}(\mathrm{x}) \mathrm{dx}=\mathrm{f}(\mathrm{x}) \int \mathrm{g}(\mathrm{x}) \mathrm{dx}-\int \mathrm{f}^{\prime}(\mathrm{x})\left(\int \mathrm{g}(\mathrm{x}) \mathrm{dx}\right) \mathrm{dx}$ - To solve the inte...
Read More →Evaluate the following integrals:
Question: Evaluate the following integrals: $\int x^{2} e^{x^{3}} \cos x^{3} d x$ Solution: Let $I=\int x^{2} e^{x^{3}} \cos x^{3} d x$ $\mathrm{x}^{3}=\mathrm{t}$ $3 x^{2} d x=d t$ $I=\frac{1}{3} \int e^{t} \cos t d t$ We know that, $\int e^{a x} \cos b x d x=\frac{e^{2 x}}{a^{2}+b^{2}}\{a \cos b x-b \sin b x\}+c$ $I=\frac{1}{3}\left[\frac{e^{t}}{2}(\cos t+\sin t)\right]+c$ $I=\frac{1}{3}\left[\frac{e^{x^{3}}}{2}\left(\cos x^{3}+\sin x^{3}\right)\right]+c$...
Read More →Evaluate the following integrals:
Question: Evaluate the following integrals: $\int e^{-2 x} \sin x d x$ Solution: Let $I=\int e^{-2 x} \sin x d x$ We know that, $\int \mathrm{e}^{\operatorname{ax}} \sin b x d x=\frac{e^{\operatorname{ax}}}{a^{2}+b^{2}}\{a \sin b x-b \cos b x\}+c$ $=\frac{e^{-2 x}}{5}\{-2 \sin x-\cos x\}+c$...
Read More →Which of the following complexes show
Question: Which of the following complexes show linkage isomerism? (i) [Co(NH3)5 (NO2)]2+ (ii) [Co(H2O)5CO]3+ (iii) [Cr(NH3)5 SCN]2+ (iv) [Fe(en)2 Cl2]+ Solution: Option (i) and (iii) are the answers....
Read More →Identify the correct statements for the behaviour
Question: Identify the correct statements for the behaviour of ethane-1, 2-diamine as a ligand. (i) It is a neutral ligand. (ii) It is a didentate ligand. (iii) It is a chelating ligand. (iv) It is a unidentate ligand. Solution: Option (i), (ii) and (iii) are the answers....
Read More →Identify the optically active compounds
Question: Identify the optically active compounds from the following : (i) [Co(en)3]3+ (ii) trans [Co(en)2 Cl2]+ (iii) cis [Co(en)2 Cl2]+ (iv) [Cr (NH3)5Cl] Solution: Option (i) [Co(en)3]3+ and (iii) cis [Co(en)2 Cl2]+ are the answers....
Read More →Which of the following complexes
Question: Which of the following complexes are heteroleptic? (i) [Cr(NH3)6]3+ (ii) [Fe(NH3)4 Cl2]+ (iii) [Mn(CN)6]4 (iv) [Co(NH3)4Cl2] Solution: Option (ii)[Fe(NH3)4 Cl2]+ and (iv)[Co(NH3)4Cl2] are the answers....
Read More →Which of the following complexes
Question: Which of the following complexes is homoleptic? (i) [Co(NH3)6]3+ (ii) [Co(NH3)4 Cl2]+ (iii) [Ni(CN)4]2 (iv) [Ni(NH3)4Cl2] Solution: Option (i)[Co(NH3)6]3+ and (iii)[Ni(CN)4]2 are the answers....
Read More →Evaluate the following integrals:
Question: Evaluate the following integrals: $\int e^{2 x} \cos ^{2} x d x$ Solution: Let $I=\int e^{2 x} \cos ^{2} x d x$ $=\frac{1}{2} \int \mathrm{e}^{2 \mathrm{x}} 2 \cos ^{2} \mathrm{x} \mathrm{dx}$ $=\frac{1}{2} \int \mathrm{e}^{2 \mathrm{x}}(1+\cos 2 \mathrm{x}) \mathrm{dx}$ $=\frac{1}{2} \int \mathrm{e}^{2 \mathrm{x}} \mathrm{dx}+\frac{1}{2} \int \mathrm{e}^{2 \mathrm{x}} \cos 2 \mathrm{xdx}$ We know that, $\int e^{a x} \cos b x d x=\frac{e^{a x}}{a^{2}+b^{2}}\{a \cos b x-b \sin b x\}+c$ ...
Read More →Evaluate the following integrals:
Question: Evaluate the following integrals: $\int \frac{1}{x^{3}} \sin (\log x) d x$ Solution: Let $I=\int \frac{1}{x^{3}} \sin (\log x) d x$ let $\log \mathrm{x}=\mathrm{t} \Rightarrow \frac{1}{\mathrm{x}} \mathrm{dx}=\mathrm{dt} \Rightarrow \mathrm{dx}=\mathrm{e}^{\mathrm{x}} \mathrm{dt}$ We know that $\int e^{2 x} \sin b x d x=\frac{e^{a x}}{a^{2}+b^{2}}\{a \sin b x-b \cos b x\}+c$ $\int e^{-2 t} \sin t d t=\frac{e^{-2 t}}{5}\{-2 \sin t-\cos t\}+c$ $I=\frac{x^{-2}}{5}\{-2 \sin (\log x)-\cos (...
Read More →Evaluate the following integrals:
Question: Evaluate the following integrals: $\int e^{x} \sin ^{2} x d x$ Solution: Let $I=\int e^{x} \sin ^{2} x d x$ $I=\frac{1}{2} \int e^{x} 2 \sin ^{2} x d x$ $=\frac{1}{2} \int \mathrm{e}^{\mathrm{x}}(1-\cos 2 \mathrm{x}) \mathrm{dx}$ Using integration by parts, $=\frac{1}{2} \int e^{x} d x-\frac{1}{2} \int e^{x} \cos 2 x d x$ We know that, $\int e^{a x} \operatorname{cosbxdx}=\frac{e^{a x}}{a^{2}+b^{2}}\{a \cos b x-b \sin b x\}+c$ $I=\frac{1}{2}\left[e^{x}-\frac{e^{x}}{5}(\cos 2 x+2 \sin 2...
Read More →Evaluate the following integrals:
Question: Evaluate the following integrals: $\int e^{2 x} \sin (3 x+1) d x$ Solution: Let $I=\int e^{2 x} \sin (3 x+1) d x$ Now Integrating by parts choosing $\sin (3 x+1)$ as first function and $e^{2 x}$ as second function we get, $I=\sin (3 x+1) \int e^{2 x} d x-\int\left(\frac{d}{d x} \sin (3 x+1) \int e^{2 x} d x\right) d x$ $I=\frac{e^{2 x}}{2} \sin (3 x+1)-\int \frac{3 e^{2 x}}{2} \cos (3 x+1) d x$ Now again integrating by parts by taking $\cos (3 x+1)$ as first function and $\mathrm{e}^{2...
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