The secondary structure of protein is stabilised by:
Question: The secondary structure of protein is stabilised by:Peptide bondglycosidic bondHydrogen bondingvan der Waals forcesCorrect Option: , 3 Solution: The secondary structure of protein includes two type : (a) $\alpha$-Helix (b) $\beta$-pleated sheet In $\alpha$-Helix structure, the poly peptide chain is coil around due to presence of Intramolecular H-Bonding....
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Question: In the above reactions, the enzyme $A$ and enzyme B respectively are :- Amylase and InvertaseInvertase and AmylaseInvertase and ZymaseZymase and InvertaseCorrect Option: , 3 Solution: Informative...
Read More →Given below are two statements.
Question: Given below are two statements. Statement I: In the titration between strong acid and weak base methyl orange is suitable as an indicator. Statement II: For titration of acetic acid with $\mathrm{NaOH}$ phenolphthalein is not a suitable indicator. In the light of the above statements, choose the most appropriate answer from the options given below:Statement I is false but Statement II is trueStatement I is true but Statement II is falseBoth Statement I and Statement II are trueBoth Sta...
Read More →Amongst the following, the linear species is:
Question: Amongst the following, the linear species is:$\mathrm{NO}_{2}$$\mathrm{Cl}_{2} \mathrm{O}$$\mathrm{O}_{3}$$\mathrm{N}_{3}^{-}$Correct Option: , 4 Solution:...
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Question: Identify the reagent(s) 'A' and condition(s) for the reaction :$\mathrm{A}=\mathrm{HCl} ;$ Anhydrous $\mathrm{AlCl}_{3}$$\mathrm{A}=\mathrm{HCl}, \mathrm{ZnCl}_{2}$$\mathrm{A}=\mathrm{Cl}_{2} ; \mathrm{UV}$ light$\mathrm{A}=\mathrm{Cl}_{2} ;$ dark, Anhydrous $\mathrm{AlCl}_{3}$Correct Option: , 3 Solution: For substitution at allylic position in the given compound, the reagent used is $\mathrm{Cl}_{2} / \mathrm{uv}$ light. The reaction is free radical halogenation....
Read More →Nitrogen can be estimated by Kjeldahl's method for which of the following compound?
Question: Nitrogen can be estimated by Kjeldahl's method for which of the following compound? Correct Option: , 2 Solution: Kjeldahl method is not applicable to compounds containing nitrogen in nitrogroup, Azo groups and nitrogen present in the ring (e.g Pyridine) as nitrogen of these compounds does not change to Ammonium sulphate under these conditions....
Read More →Given below are two statements :
Question: Given below are two statements : Statement-I : 2-methylbutane on oxidation with $\mathrm{KMnO}_{4}$ gives 2-methylbutan-2-ol. Statement-II : $\mathrm{n}$-alkanes can be easily oxidised to corresponding alcohol with $\mathrm{KMnO}_{4}$. Choose the correct option : Both statement I and statement II are correctBoth statement I and statement II are incorrectStatement I is correct but Statement II is incorrectStatement I is incorrect but Statement II is correctCorrect Option: , 3 Solution: ...
Read More →The conversion of hydroxyapatite occurs due to presence of
Question: The conversion of hydroxyapatite occurs due to presence of $\mathrm{F}^{-}$ions in water. The correct formula of hydroxyapatite is:$\left[3 \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2} \cdot \mathrm{Ca}(\mathrm{OH})_{2}\right]$$\left[3 \mathrm{Ca}(\mathrm{OH})_{2} \cdot \mathrm{CaF}_{2}\right]$$\left[\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2} \cdot \mathrm{CaF}_{2}\right]$$\left[3 \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2} \cdot \mathrm{CaF}_{2}\right]$Correct Option: 1, S...
Read More →Identify the elements X and Y using the ionisation energy values given below :
Question: Identify the elements X and Y using the ionisation energy values given below : X = Na ; Y = MgX = Mg ; Y = FX = Mg ; Y = NaX = F ; Y = MgCorrect Option: 1 Solution: $\mathrm{Na} \rightarrow[\mathrm{Ne}] 3 \mathrm{~s}^{1} \mathrm{IE}_{1}$ is very low but $\mathrm{IE}_{2}$ is very high due to stable noble gas configuration of $\mathrm{Na}^{+}$ $\mathrm{Mg} \rightarrow[\mathrm{Ne}] 3 \mathrm{~s}^{2} \mathrm{IE}_{1} \ \mathrm{IE}_{2} \rightarrow$ Low $\mathrm{IE}_{3}$ is very high....
Read More →Match List-I with List-II :
Question: Match List-I with List-II : Choose the correct match : (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)(a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)(a)-(iii), (b)-(ii), (c)-(iv), (d)-(i)(a)-(i), (b)-(ii), (c)-(iv), (d)-(iii)Correct Option: , 2 Solution: Artificial sweetner : Sucralose Antiseptic : Bithional Preservative: Sodium Benzoate Glyceryl ester of stearic acid : Sodium steasate...
Read More →Which of the following reduction reaction CANNOT be carried out with coke ?
Question: Which of the following reduction reaction CANNOT be carried out with coke ?$\mathrm{Al}_{2} \mathrm{O}_{3} \rightarrow \mathrm{Al}$$\mathrm{ZnO} \rightarrow \mathrm{Zn}$$\mathrm{Fe}_{2} \mathrm{O}_{3} \rightarrow \mathrm{Fe}$$\mathrm{Cu}_{2} \mathrm{O} \rightarrow \mathrm{Cu}$Correct Option: 1 Solution: Reduction of $\mathrm{Al}_{2} \mathrm{O}_{3} \rightarrow \mathrm{Al}$ is carried out by electrolytic reduction of its fused salts. $\mathrm{ZnO}, \mathrm{Fe}_{2} \mathrm{O}_{3} \ \mathr...
Read More →The common positive oxidation states for an element with atomic number 24, are :
Question: The common positive oxidation states for an element with atomic number 24, are :$+2$ to $+6$$+1$ and $+3$ to $+6$$+1$ and $+3$$+1$ to $+6$Correct Option: 1 Solution: $\operatorname{Cr}(Z=24)$ $[\mathrm{Ar}] 4 \mathrm{~s}^{1} 3 \mathrm{~d}^{5} \mathrm{Cr}$ shows common oxidation states starting from $+2$ to $+6$....
Read More →The correct options for the products A and B of
Question: The correct options for the products $\mathbf{A}$ and $\mathbf{B}$ of the following reactions are : Correct Option: , 2 Solution:...
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Question: In the above reaction, the reagent "A" is$\mathrm{NaBH}_{4}, \mathrm{H}_{3} \mathrm{O}^{+}$$\mathrm{LiAlH}_{4}$Alkaline $\mathrm{KMnO}_{4}, \mathrm{H}^{+}$$\mathrm{HCl}, \mathrm{Zn}-\mathrm{Hg}$Correct Option: , 3 Solution:...
Read More →Primary, secondary and tertiary amines can be separated using :-
Question: Primary, secondary and tertiary amines can be separated using :-Para-Toluene sulphonyl chlorideChloroform and $\mathrm{KOH}$Benzene sulphonic acidAcetyhamideCorrect Option: 1 Solution: Primary amines react with Para Toluene sulfonyl chloride to form a precipitate that is soluble in $\mathrm{NaOH}$. Secondary amines reacts with para toluene sulfonyl chloride to give a precipitate that is insoluble in $\mathrm{NaOH}$. Tertiary amines do not react with para toluen....
Read More →Complete combustion of
Question: Complete combustion of $3 \mathrm{~g}$ of ethane gives $\mathrm{x} \times 10^{22}$ molecules of water. The value of $\mathrm{x}$ is________. (Round off to the Nearest Integer). [Use : $\mathrm{N}_{\mathrm{A}}=6.023 \times 10^{23}$; Atomic masses in $\mathrm{u}$ $: \mathrm{C}: 12.0 ; \mathrm{O}: 16.0 ; \mathrm{H}: 1.0]$ Solution: $\mathrm{C}_{2} \mathrm{H}_{6} \rightarrow 3 \mathrm{H}_{2} \mathrm{O}$ No. of molecules $=0.3 \times 6.023 \times 10^{23}$ $=18.069 \times 10^{22}$...
Read More →The green house gas/es is (are) :
Question: The green house gas/es is (are) : (A) Carbon dioxide (B) Oxygen (C) Water vapour (D) Methane Choose the most appropriate answer from the options given below :(A) and (C) only(A) only(A), (C) and (D) only(A) and (B) onlyCorrect Option: , 3 Solution: The green house gases are $\mathrm{CO}_{2}, \mathrm{H}_{2} \mathrm{O}_{\text {(vapour) }} \$ $\mathrm{CH}_{4}$....
Read More →For the reaction
Question: For the reaction $2 \mathrm{Fe}^{3+}(\mathrm{aq})+2 \mathrm{I}^{-}(\mathrm{aq}) \rightarrow 2 \mathrm{Fe}^{2+}(\mathrm{aq})+\mathrm{I}_{2}(\mathrm{~s})$ the magnitude of the standard molar free energy change, $\Delta_{\mathrm{r}} \mathrm{G}_{\mathrm{m}}^{\circ}=-$ $\mathrm{kJ}$ (Round off to the Nearest Integer). Solution: $\mathrm{E}_{1}^{0}+2 \mathrm{E}_{2}^{0}=3 \mathrm{E}_{3}^{0}$ $\mathrm{E}_{1}^{0}=3 \mathrm{E}_{3}^{0}-2 \mathrm{E}_{2}^{0}$ $=3(-0.036)-2(-0.44)$ $=+0.772 \mathrm{...
Read More →Given below are two statements :
Question: Given below are two statements : Statement I : The limiting molar conductivity of $\mathrm{KCl}$ (strong electrolyte) is higher compared to that of $\mathrm{CH}_{3} \mathrm{COOH}$ (weak electrolyte). Statement II : Molar conductivity decreases with decrease in concentration of electrolyte. In the light of the above statements, choose the most appropriate answer from the options given below:Statement I is true but Statement II is false.Statement I is false but Statement II is true.Both ...
Read More →Match List-I with List-II :
Question: Match List-I with List-II : Choose the correct answer from the options given below : (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)(a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)$(\mathrm{a})-(\mathrm{ii}),(\mathrm{b})-(\mathrm{i}),(\mathrm{c})-(\mathrm{iii}),(\mathrm{d})-(\mathrm{iv})$(a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)Correct Option: 1 Solution:...
Read More →2 molal solution of a weak acid HA has a freezing
Question: 2 molal solution of a weak acid HA has a freezing point of $3.885^{\circ} \mathrm{C}$. The degree of dissociation of this acid is_______ $\times 10^{-3}$. (Round off to the Nearest Integer). [Given : Molal depression constant of water $=$ $1.85 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$ Freezing point of pure water $\left.=0^{\circ} \mathrm{C}\right]$ Solution: $\Delta \mathrm{T}_{\mathrm{f}}=(1+\alpha) \mathrm{K}_{\mathrm{f}} \mathrm{m}$ $\alpha=0.05=50 \times 10^{-3}$...
Read More →The total number of unpaired electrons present
Question: The total number of unpaired electrons present in the complex $\mathrm{K}_{3}\left[\mathrm{Cr}\right.$ (oxalate) $\left._{3}\right]$ is Solution: $\mathrm{K}_{3}\left[\mathrm{Cr}(\text { oxalate })_{3}\right]$ Chromium is in $+3$ oxidation state. Number of unpaired electrons in $\mathrm{Cr}^{+3}$ will be 3 ....
Read More →A reaction of 0.1 mole of Benzylamine with bromomethane
Question: A reaction of $0.1$ mole of Benzylamine with bromomethane gave $23 \mathrm{~g}$ of Benzyl trimethyl ammonium bromide. The number of moles of bromomethane consumed in this reaction are $\mathrm{n} \times 10^{-1}$, when $\mathrm{n}=$ . (Round off to the Nearest Integer). (Given: Atomic masses: $\mathrm{C}: 12.0 \mathrm{u}$, $\mathrm{H}: 1.0 \mathrm{u}, \mathrm{N}: 14.0 \mathrm{u}, \mathrm{Br}: 80.0 \mathrm{u}]$ Solution:...
Read More →The set that represents the pair of neutral oxides of nitrogen is :
Question: The set that represents the pair of neutral oxides of nitrogen is : $\mathrm{NO}$ and $\mathrm{N}_{2} \mathrm{O}$$\mathrm{N}_{2} \mathrm{O}$ and $\mathrm{N}_{2} \mathrm{O}_{3}$$\mathrm{N}_{2} \mathrm{O}$ and $\mathrm{NO}_{2}$$\mathrm{NO}$ and $\mathrm{NO}_{2}$Correct Option: 1 Solution: $\mathrm{N}_{2} \mathrm{O}$ and $\mathrm{NO}$ are neutral oxides of nitrogen $\mathrm{NO}_{2}$ and $\mathrm{N}_{2} \mathrm{O}_{3}$ are acidic oxides....
Read More →________grams of 3-Hydroxy propanal
Question: ________grams of 3-Hydroxy propanal $(\mathrm{MW}=74)$ must be dehydrated to produce $7.8 \mathrm{~g}$ of acrolein $(\mathrm{MW}=56)\left(\mathrm{C}_{3} \mathrm{H}_{4} \mathrm{O}\right)$ if the percentage yield is 64. (Round off to the Nearest Integer). [Given : Atomic masses: C: $12.0 \mathrm{u}$, $\mathrm{H}: 1.0 \mathrm{u}, \mathrm{O}: 16.0 \mathrm{u}]$ Solution: $\frac{\mathrm{x}}{74} \mathrm{~mol}$ $\frac{x}{74} \times 0.64=\frac{7.8}{56}$ $x=16.10$ $\simeq 16.00$...
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