The increasing order of the following compounds towards HCN addition is :
Question: The increasing order of the following compounds towards HCN addition is : (iii) $$ (iv) $$ (ii) $$ (i)(iii) $$ (iv) $$ (i) $$ (ii)(iii) $$ (i) $$ (iv) $$ (ii)(i) $$ (iii) $$ (iv) $$ (ii)Correct Option: , 3 Solution: Increasing order of reactivity towards $\mathrm{HCN}$ addition...
Read More →Which of the following compounds will show retention in
Question: Which of the following compounds will show retention in configuration on nucleophic substitution by $\mathrm{OH}$ ion?Correct Option: 1 Solution: As language given, we have to go with option (1) as stereochemistry of chiral centre is not distortet....
Read More →Which one of the following graphs is not correct for ideal gas?
Question: Which one of the following graphs is not correct for ideal gas? IIIIIIIVCorrect Option: 1 Solution: $\mathrm{PM}=\mathrm{dRT} \Rightarrow \mathrm{d} \propto \frac{1}{\mathrm{~T}}$...
Read More →The complex that can show optical activity is:
Question: The complex that can show optical activity is: trans- $\left[\mathrm{Fe}\left(\mathrm{NH}_{3}\right)_{2}(\mathrm{CN})_{4}\right]^{-}$cis- $\left[\mathrm{Fe}\left(\mathrm{NH}_{3}\right)_{2}(\mathrm{CN})_{4}\right]^{-}$cis- $\left[\mathrm{CrCl}_{2}(\mathrm{ox})_{2}\right]^{3-}(\mathrm{ox}=$ oxalate $)$trans- $\left[\mathrm{Cr}\left(\mathrm{Cl}_{2}\right)(\mathrm{ox})_{2}\right]^{3-}$Correct Option: 3, Solution:...
Read More →An open beaker of water in equilibrium with
Question: An open beaker of water in equilibrium with water vapour is in a sealed container. When a few grams of glucose are added to the beaker of water, the rate at which water molecules :leaves the vapour increasesleaves the solution increasesleaves the solution decreasesleaves the vapour decreasesCorrect Option: 1 Solution: With addition of solute in solvent, surface area for vapourisation decreases causes lowering in vapour pressure...
Read More →The major aromatic product C in the following reaction sequence will be :
Question: The major aromatic product $\mathrm{C}$ in the following reaction sequence will be : Correct Option: , 2 Solution:...
Read More →In Carius method of estimation of halogen,
Question: In Carius method of estimation of halogen, $0.172 \mathrm{~g}$ of an organic compound showed presence of $0.08 \mathrm{~g}$ of bromine. Which of these is the correct structure of the compound :Correct Option: 1 Solution: In Carius method mass of organic compound $=0.172 \mathrm{gm}$ mass of Bromine $=0.08 \mathrm{gm}$ Hence $\%$ of Bromine $=\frac{0.08}{0.172} \times 100$ $=46.51 \%$...
Read More →Consider that a d^6 metal ion M^2+ forms a complex with aqua ligands,
Question: Consider that a $\mathrm{d}^{6}$ metal ion $\left(\mathrm{M}^{2+}\right)$ forms a complex with aqua ligands, and the spin only magnetic moment of the complex is $4.90 \mathrm{BM}$. The geometry and the crystal field stabilization energy of the complex is :tetrahedral and $-1.6 \Delta_{t}+1 \mathrm{P}$tetrahedral and $-0.6 \Delta_{1}$octahedral and $-1.6 \Delta_{0}$octahedral and $-2.4 \Delta_{0}+2 \mathrm{P}$Correct Option: , 2 Solution: If spin only magnetic moment of the complex is $...
Read More →For octahedral Mn(II) and tetrahedral Ni(II) complexes,
Question: For octahedral Mn(II) and tetrahedral Ni(II) complexes, consider the following statements : (I) both the complexes can be high spin (II) $\mathrm{Ni}$ (II) complex can very rarely be low spin. (III) with strong field ligands, $\mathrm{Mn}$ (II) complexes can be low spin. (IV) aqueous solution of $\mathrm{Mn}$ (II) ions is yellow in color. The correct statements are :(I), (III) and (IV) only(II), (III) and (IV) only(I), (II) and (III) only(I) and (II) onlyCorrect Option: , 3 Solution: (...
Read More →The metal mainly used in devising photoelectric cells is:
Question: The metal mainly used in devising photoelectric cells is:$\mathrm{Na}$$\mathrm{Rb}$$\mathrm{Li}$$\mathrm{Cs}$Correct Option: , 4 Solution: Cs used in photoelectric cell as it has least ionisation energy....
Read More →The statement that is not true about ozone is :
Question: The statement that is not true about ozone is :in the stratosphere, it forms a protective shield against UV radiation.it is a toxic gas and its reaction with NO gives $\mathrm{NO}_{2}$.in the atmosphere, it is depleted by CFCs.in the stratophere, CFCs release chlorine free radicals (Cl) which reacts with $\mathrm{O}_{3}$ to give chlorine dioxide radicals.Correct Option: , 4 Solution: In the stratosphere, CFCs release chlorine free radical (Ci) $\mathrm{CF}_{2} \mathrm{Cl}_{2}(\mathrm{~...
Read More →In general, the property (magnitudes only) that shows an opposite trend
Question: In general, the property (magnitudes only) that shows an opposite trend in comparison to other properties across a period isElectronegativityElectron gain enthalpyIonization enthalpyAtomic radiusCorrect Option: , 4 Solution: In general across a period atomic radius decreases while ionisation enthalpy, electron gain enthalpy and electronegativity increases because effective nuclear charge $\left(Z_{\mathrm{eff}}\right)$ increases....
Read More →On heating compound (A) gives a gas (B) which is constituent of air.
Question: On heating compound (A) gives a gas (B) which is constituent of air. This gas when treated with $\mathrm{H}_{2}$ in the presence of a catalyst gives another gas (C) which is basic in nature. (A) should not be:$\left(\mathrm{NH}_{4}\right)_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$$\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}$$\mathrm{NaN}_{3}$$\mathrm{NH}_{4} \mathrm{NO}_{2}$Correct Option: , 2 Solution: Basic gas $(\mathrm{C})$ must be ammonia $\left(\mathrm{NH}_{3}\right)$. It means (B) gas ...
Read More →If AB4 molecule is a polar molecule,
Question: If $\mathrm{AB}_{4}$ molecule is a polar molecule, a possible geometry of $\mathrm{AB}_{4}$ is :Square pyramidalTetrahedralSquare planarRectangular planarCorrect Option: 1 Solution: (1) If $\mathrm{AB}_{4}$ molecule is a square pyramidal then it has one lone pair and their structure should be and it should be polar because dipole moment of lone pair of 'A' never be cancelled by others. (2) If $\mathrm{AB}_{4}$ molecule is a tetrahedral then it has no lone pair and their structure shoul...
Read More →Solve this following
Question: If $\overrightarrow{\mathrm{x}}$ and $\overrightarrow{\mathrm{y}}$ be two non-zero vectors such that $|\overrightarrow{\mathrm{x}}+\overrightarrow{\mathrm{y}}|=|\overrightarrow{\mathrm{x}}|$ and $2 \overrightarrow{\mathrm{x}}+\lambda \overrightarrow{\mathrm{y}}$ is perpendicular to $\overrightarrow{\mathrm{y}}$, then the value of $\lambda$ is Solution: $|\overrightarrow{\mathrm{x}}+\overrightarrow{\mathrm{y}}|=|\overrightarrow{\mathrm{x}}|$ $\sqrt{|\overrightarrow{\mathrm{x}}|^{2}+|\ov...
Read More →Solve this following
Question: Consider the data on $x$ taking the values 0,2, $4,8, \ldots, 2^{\mathrm{n}}$ with frequencies ${ }^{n} C_{0},{ }^{n} C_{1},{ }^{n} C_{2}, \ldots$ ${ }^{n} C_{n}$ respectively. If the mean of this data is $\frac{728}{2^{\mathrm{n}}}$, then $\mathrm{n}$ is equal to Solution: Mean $=\frac{\sum x_{i} f_{i}}{\sum f_{i}}=\frac{\sum_{r=1}^{n} 2^{r}{ }^{n} C_{r}}{\sum_{r=0}^{n}{ }^{n} C_{r}}$ Mean $=\frac{(1+2)^{\mathrm{n}}-{ }^{\mathrm{n}} \mathrm{C}_{0}}{2^{\mathrm{n}}}=\frac{728}{2^{\mathr...
Read More →For the following Assertion and Reason, the correct option is
Question: For the following Assertion and Reason, the correct option is Assertion (A) : When Cu (II) and sulphide ions are mixed, they react together extremely quickly to give a solid. Reason $(\mathbf{R}):$ The equilibrium constant of $\mathrm{Cu}^{2+}(\mathrm{aq})+\mathrm{S}^{2-}(\mathrm{aq}) \rightleftharpoons \mathrm{CuS}(\mathrm{s})$ is high because the solubility product is low.Both $(A)$ and $(R)$ are true and $(R)$ is the explanation for (A)Both (A) and (R) are false(A) is false and (R) ...
Read More →The number of words (with or without meaning)
Question: The number of words (with or without meaning) that can be formed from all the letters of the word "LETTER" in which vowels never come together is Solution: LETTER vowels $=\mathrm{EE}$, consonant $=\mathrm{LTTR}$ $_{-} L_{-} T_{-} T_{-} R_{-}$ $\frac{4 !}{2 !} \times{ }^{5} \mathrm{C}_{2} \times \frac{2 !}{2 !}=12 \times 10=120$...
Read More →The figure that is not a direct manifestation of the quantum nature of atoms is :
Question: The figure that is not a direct manifestation of the quantum nature of atoms is :Correct Option: 1 Solution: Photoelectric effect (option 2), atomic spectrum (option 3) and Black body radiations (option 4) may be explained by quantum theory. As on increasing temperature, all the values of internal energy becomes possible, it is not directly explained from quantum theory....
Read More →Suppose that a function
Question: Suppose that a function $f: \mathrm{R} \rightarrow \mathrm{R}$ satisfies $f(\mathrm{x}+\mathrm{y})=f(\mathrm{x}) f(\mathrm{y})$ for all $\mathrm{x}, \mathrm{y} \in \mathrm{R}$ and $f(1)=3$. If $\sum_{\mathrm{i}=1}^{\mathrm{n}} f(\mathrm{i})=363$, then $\mathrm{n}$ is equal to Solution: $f(\mathrm{x}+\mathrm{y})=f(\mathrm{x}) f(\mathrm{y})$ put $x=y=1 \quad f(2)=(f(1))^{2}=3^{2}$ put $x=2, y=1 \quad f(3)=(f(1))^{3}=3^{3}$ Similarly $f(\mathrm{x})=3^{\mathrm{x}}$ $\sum_{\mathrm{i}=1}^{\m...
Read More →The IUPAC name for the following compound is:
Question: The IUPAC name for the following compound is:2,5 -dimethyl-6-carboxy-hex-3-enal6 -formyl-2-methyl-hex-3-enoic acid2,5 -dimethyl-5-carboxy-hex-3-enal2,5 -dimethyl-6-oxo-hex-3-enoic acidCorrect Option: , 4 Solution: 2,5 -dimethyl-6-oxo-hex-3-enoic acid...
Read More →The sum of distinct values of
Question: The sum of distinct values of $\lambda$ for which the system of equations $(\lambda-1) x+(3 \lambda+1) y+2 \lambda z=0$ $(\lambda-1) x+(4 \lambda-2) y+(\lambda+3) z=0$ $2 x+(3 \lambda+1) y+3(\lambda-1) z=0$ has non-zero solutions, is Solution: $(\lambda-1) x+(3 \lambda+1) y+2 \lambda z=0$ $(\lambda-1) x+(4 \lambda-2) y+(\lambda+3) z=0$ $2 x+(3 \lambda+1) y+(3 \lambda-3) z=0$ $\left|\begin{array}{ccc}\lambda-1 3 \lambda+1 2 \lambda \\ \lambda-1 4 \lambda-2 \lambda+3 \\ 2 3 \lambda+1 3 \...
Read More →The centre of the circle passing through the
Question: The centre of the circle passing through the point $(0,1)$ and touching the parabola $\mathrm{y}=\mathrm{x}^{2}$ at the point $(2,4)$ is :$\left(\frac{3}{10}, \frac{16}{5}\right)$$\left(\frac{-16}{5}, \frac{53}{10}\right)$$\left(\frac{6}{5}, \frac{53}{10}\right)$$\left(\frac{-53}{10}, \frac{16}{5}\right)$Correct Option: , 2 Solution: $y=x^{2}$ $\left.\frac{\mathrm{dy}}{\mathrm{dx}}\right|_{\mathrm{P}}=4$ $(y-4)=4(x-2)$ $4 x-y-4=0$ Circle : $(x-2)^{2}+(y-4)^{2}+\lambda(4 x-y-4)=0$ passe...
Read More →Solve this following
Question: If $y=\left(\frac{2}{\pi} x-1\right) \operatorname{cosecx}$ is the solution of the differential equation, $\frac{d y}{d x}+p(x) y=\frac{2}{\pi} \operatorname{cosec} x, 0x\frac{\pi}{2}$, then the function $\mathrm{p}(\mathrm{x})$ is equal to $\cot x$$\tan x$$\operatorname{cosecx}$$\operatorname{secx}$Correct Option: 1, Solution: $y=\left(\frac{2 x}{\pi}-1\right) \operatorname{cosecx}$ $\ldots(1)$ $\frac{d y}{d x}=\frac{2}{\pi} \operatorname{cosecx}-\left(\frac{2 x}{\pi}-1\right) \operat...
Read More →Solve this following
Question: Let $\mathrm{L}$ denote the line in the $\mathrm{xy}$-plane with $\mathrm{x}$ and $y$ intercepts as 3 and 1 respectively. Then the image of the point $(-1,-4)$ in this line is : $\left(\frac{8}{5}, \frac{29}{5}\right)$$\left(\frac{29}{5}, \frac{11}{5}\right)$$\left(\frac{11}{5}, \frac{28}{5}\right)$$\left(\frac{29}{5}, \frac{8}{5}\right)$Correct Option: , 3 Solution: $\mathrm{L}: \frac{\mathrm{x}}{3}+\frac{\mathrm{y}}{1}=1 \Rightarrow \mathrm{x}+3 \mathrm{y}-3=0$ Image of point $(-1,-4...
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