For a d4 metal ion in an octahedral field,
Question: For a $\mathrm{d}^{4}$ metal ion in an octahedral field, the correct electronic configuration is :$\mathrm{t}_{2 \mathrm{~g}}^{4} \mathrm{e}_{\mathrm{g}}^{0}$ when $\Delta_{\mathrm{O}}\mathrm{P}$$\mathrm{e}_{\mathrm{g}}^{2} \mathrm{t}_{2 \mathrm{~g}}^{2}$ when $\Delta_{\mathrm{O}}\mathrm{P}$$\mathrm{t}_{2 \mathrm{~g}}^{3} \mathrm{e}_{\mathrm{g}}^{1}$ when $\Delta_{\mathrm{O}}\mathrm{P}$$\mathrm{t}_{2 \mathrm{~g}}^{3} \mathrm{e}_{\mathrm{g}}^{1}$ when $\Delta_{\mathrm{O}}\mathrm{P}$Corr...
Read More →Magnetic materials used for making permanent magnets
Question: Magnetic materials used for making permanent magnets (P) and magnets in a transformer (T) have different properties of the following, which property best matches for the type of magnet required ? $\mathrm{T}$ : Large retentivity, small coercivity$P$ : Small retentivity, large coercivityT : Large retentivity, large coercivity$\mathrm{P}$ : Large retentivity, large coercivityCorrect Option: , 4 Solution: As for permanent magnet large retentivity and large coercivity required...
Read More →A crystal is made up of metal ions 'M1' and 'M2' and oxide ions.
Question: A crystal is made up of metal ions ' $M_{1}{ }^{\prime}$ ana ' $M_{2}{ }^{\prime}$ and oxide ions. Oxide ions form a ccp lattice structure. The cation ' $\mathrm{M}_{1}{ }^{\prime}$ occupies $50 \%$ of octahedral voids and the cation ' $M_{2}$ ' occupies $12.5 \%$ of tetrahedral voids of oxide lattice. The oxidation numbers of ' $\mathrm{M}_{1}$ ' and ' $\mathrm{M}_{2}$ ' are, respectively:$+2,+4$$+3,+1$$+1,+3$$+4,+2$Correct Option: 1 Solution: $\mathrm{M}_{1}=50 \%$ of O.V. $\Rightarr...
Read More →Consider four conducting materials copper, tungsten, mercury and aluminium with
Question: Consider four conducting materials copper, tungsten, mercury and aluminium with resistivity $\rho_{\mathrm{C}}\rho_{\mathrm{T}}\rho_{\mathrm{M}}$ and $\rho_{\mathrm{A}}$ respectively. Then: $\rho_{\mathrm{A}}\rho_{\mathrm{T}}\rho_{\mathrm{C}}$$\rho_{\mathrm{C}}\rho_{\mathrm{A}}\rho_{\mathrm{T}}$$\rho_{\mathrm{A}}\rho_{\mathrm{M}}\rho_{\mathrm{C}}$$\rho_{\mathrm{M}}\rho_{\mathrm{A}}\rho_{\mathrm{C}}$Correct Option: , 4 Solution: $\rho_{\mathrm{M}}\rho_{\mathrm{A}}\rho_{\mathrm{C}}$...
Read More →A beam of protons with speed
Question: A beam of protons with speed $4 \times 10^{5} \mathrm{~ms}^{-1}$ enters a uniform magnetic field of $0.3 \mathrm{~T}$ at an angle of $60^{\circ}$ to the magnetic field. The pitch of the resulting helical path of protons is close to: (Mass of the proton $=1.67 \times 10^{-27} \mathrm{~kg}$, charge of the proton $=1.69 \times 10^{-19} \mathrm{C}$ $12 \mathrm{~cm}$$4 \mathrm{~cm}$$5 \mathrm{~cm}$$2 \mathrm{~cm}$Correct Option: , 2 Solution: Pitch $=\frac{2 \pi \mathrm{m}}{\mathrm{qB}} \ma...
Read More →For the given cell ;
Question: For the given cell ; $\mathrm{Cu}(\mathrm{s})\left|\mathrm{Cu}^{2+}\left(\mathrm{C}_{1} \mathrm{M}\right) \| \mathrm{Cu}^{2+}\left(\mathrm{C}_{2} \mathrm{M}\right)\right| \mathrm{Cu}(\mathrm{s})$ change in Gibbs energy $(\Delta \mathrm{G})$ is negative, if :$\mathrm{C}_{1}=2 \mathrm{C}_{2}$$\mathrm{C}_{2}=\mathrm{Cl} / \sqrt{2}$$\mathrm{C}_{1}=\mathrm{C}_{2}$$\mathrm{C}_{2}=\sqrt{2} \mathrm{C}_{1}$Correct Option: , 4 Solution: $\Delta \mathrm{G}=-\mathrm{n} \mathrm{F} \mathrm{E}_{\math...
Read More →A particle of mass $m$ with an initial velocity
Question: A particle of mass $m$ with an initial velocity $u \hat{i}$ collides perfectly elastically with a mass $3 \mathrm{~m}$ at rest. It moves with a velocity $v \hat{j}$ after collision, then, $v$ is given by : $\mathrm{v}=\sqrt{\frac{2}{3}} \mathrm{u}$$\mathrm{v}=\frac{1}{\sqrt{6}} \mathrm{u}$$v=\frac{u}{\sqrt{3}}$$\mathrm{v}=\frac{\mathrm{u}}{\sqrt{2}}$Correct Option: , 4 Solution: From momentum conservation $\vec{P}_{i}=\vec{P}_{f}$ $\mathrm{m}(\mathrm{ui})+3 \mathrm{~m}(0)=\mathrm{mvj}+...
Read More →The reaction of NO with N2O4 at 250k givs:
Question: The reaction of $\mathrm{NO}$ with $\mathrm{N}_{2} \mathrm{O}_{4}$ at $250 \mathrm{~K}$ gives :$\mathrm{N}_{2} \mathrm{O}_{5}$$\mathrm{NO}_{2}$$\mathrm{N}_{2} \mathrm{O}$$\mathrm{N}_{2} \mathrm{O}_{3}$Correct Option: , 4 Solution:...
Read More →Match the following:
Question: Match the following: (i)-(d), (ii)-(c), (iii)-(e), (iv)-(a)(i)-(b), (ii)-(d), (iii)-(e), (iv)-(a)(i)-(d), (ii)-(c), (iii)-(b), (iv)-(e)(i)-(b), (ii)-(a), (iii)-(c), (iv)-(d)Correct Option: 1 Solution:...
Read More →Solve this following
Question: A spherical mirror is obtained as shown in the figure from a hollow glass sphere. If an object is positioned in front of the mirror, what will be the nature and magnification of the image of the object ? (Figure drawn as schematic and not to scale) Inverted, real and magnifiedErect, virtual and magnifiedErect, virtual and unmagnifiedInverted, real and unmagnifiedCorrect Option: 1 Solution: $\mathrm{f}=\frac{-8}{2}=-4 \mathrm{~cm}$ $\mathrm{u}=-10 \mathrm{~cm}$ $\mathrm{v}=?$ as $\frac{...
Read More →Dihydrogen of high purity (>99.95 %) is obtained through:
Question: Dihydrogen of high purity $(99.95 \%)$ is obtained through:the electrolysis of warm $\mathrm{Ba}(\mathrm{OH})_{2}$ solution using Ni electrodes.the reaction of $\mathrm{Zn}$ with dilute $\mathrm{HCl}$the electrolysis of brine solution.the electrolysis of acidified water using Pt electrodes.Correct Option: 1 Solution: High purity $(99.95 \%)$ dihydrogen is obtained by electrolysing warm aqueous barium hydroxide solution between nickel electrodes....
Read More →The IUPAC name of the following compound is :
Question: The IUPAC name of the following compound is : 3 -amino-4-hydroxymethyl-5-nitrobenzaldehyde2 -nitro-4-hydroxymethyl-5-aminobenzaldehyde4-amino-2-formyl-5-hydroxymethylnitrobenzene5 -amino-4-hydroxymethyl-2-nitrobenzaldehydeCorrect Option: , 4 Solution: 5 -amino-4-hydroxymethyl-2-nitrobenzaldehyde...
Read More →Reaction of an inorganic sulphite X with dilute
Question: Reaction of an inorganic sulphite $\mathrm{X}$ with dilute $\mathrm{H}_{2} \mathrm{SO}_{4}$ generates compound $\mathrm{Y}$. Reaction of $\mathrm{Y}$ with $\mathrm{NaOH}$ gives $X$. Further, the reaction of $X$ with $\mathrm{Y}$ and water affords compound $\mathrm{Z}$. $\mathrm{Y}$ and $Z$, respectively, are:$\mathrm{S}$ and $\mathrm{Na}_{2} \mathrm{SO}_{3}$$\mathrm{SO}_{2}$ and $\mathrm{NaHSO}_{3}$$\mathrm{SO}_{3}$ and $\mathrm{NaHSO}_{3}$$\mathrm{SO}_{2}$ and $\mathrm{Na}_{2} \mathrm...
Read More →Solve this following
Question: Considering that $\Delta_{0}\mathrm{P}$, the magnetic moment (in BM) of $\left[\mathrm{Ru}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ would be Solution: Magnetic moment (in B.M.) of $\left[\mathrm{Ru}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ would be; while considering that $\Delta_{0}P$, $\mathrm{Ru}_{(44)} ;[\mathrm{Kr}] 4 \mathrm{~d}^{7} 5 \mathrm{~s}^{1} \quad$ (in ground state) $\Rightarrow$ In $\mathrm{Ru}^{2+} \Rightarrow 4 \mathrm{~d}^{6} \Rightarrow\l...
Read More →Mischmetal is an alloy consisting mainly of:
Question: Mischmetal is an alloy consisting mainly of:lanthanoid metalsactinoid metalsactinoid and transition metalslanthanoid and actinoid metalsCorrect Option: 1 Solution: (1) lanthanoid metals...
Read More →Solve this following
Question: The volume, in $\mathrm{mL}$, of $0.02 \mathrm{M} \mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$ solution required to react with $0.288 \mathrm{~g}$ of ferrous oxalate in acidic medium is (Molar mass of $\mathrm{Fe}=56 \mathrm{~g} \mathrm{~mol}^{-1}$ ) Solution: $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}+\mathrm{FeC}_{2} \mathrm{O}_{4} \longrightarrow \mathrm{Cr}^{+3}+\mathrm{Fe}^{+3}+\mathrm{CO}_{2}$ $\mathrm{n}=6 \quad \mathrm{n}=3$ $\frac{0.02 \times 6 \times V(\mathrm{~mL})}{10...
Read More →The correct match between Item-I and Item-II :
Question: The correct match between Item-I and Item-II : (a) - (III), (b) - (IV), (c) - (I), (d) - (II)(a) - (IV), (b) - (III), (c) - (II), (d) - (I)(a) - (IV), (b) - (III), (c) - (I), (d) - (II)(a) - (III), (b) - (IV), (c) - (II), (d) - (I)Correct Option: , 2 Solution:...
Read More →Solve this following
Question: For a reaction $\mathrm{X}+\mathrm{Y} \rightleftharpoons 2 \mathrm{Z}, 1.0 \mathrm{~mol}$ of $\mathrm{X}, 1.5$ mol of $\mathrm{Y}$ and $0.5 \mathrm{~mol}$ of $\mathrm{Z}$ were taken in a 1 $\mathrm{L}$ vessel and allowed to react. At equilibrium, the concentration of $\mathrm{Z}$ was $1.0 \mathrm{~mol} \mathrm{~L}^{-1}$. The equilibrium constant of the reaction is $\frac{x}{15}$. The value of $x$ is Solution: $\begin{array}{llll} \mathrm{X} +\mathrm{Y} =2 \mathrm{Z} \\ \mathrm{t}=0 1 1...
Read More →The element that can be refined by distillation is :
Question: The element that can be refined by distillation is :nickelzincgalliumtinCorrect Option: , 2 Solution: (2) zinc...
Read More →For a dimerization reaction,
Question: For a dimerization reaction, $2 \mathrm{~A}(\mathrm{~g}) \rightarrow \mathrm{A}_{2}(\mathrm{~g})$ at $298 \mathrm{~K}, \Delta \mathrm{U}^{\ominus},=-20 \mathrm{~kJ} \mathrm{~mol}^{-1}, \Delta \mathrm{S}^{\ominus}=-30 \mathrm{~J}$ $\mathrm{K}^{-1} \mathrm{~mol}^{-1}$, then the $\Delta \mathrm{G}^{\ominus}$ will be J Solution: $\Delta \mathrm{G}^{\circ}=\Delta \mathrm{H}^{\circ}-\mathrm{T} \Delta \mathrm{S}^{\circ}$ $=\left(\Delta U^{\circ}+\Delta n_{g} R T\right)-T \Delta S^{\circ}$ $\l...
Read More →The value of KC is 64 at 800 K for the reaction
Question: The value of $K_{C}$ is 64 at $800 K$ for the reaction $\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})$ The value of $K_{C}$ for the following reaction is : $\mathrm{NH}_{3}(\mathrm{~g}) \rightleftharpoons \frac{1}{2} \mathrm{~N}_{2}(\mathrm{~g})+\frac{3}{2} \mathrm{H}_{2}(\mathrm{~g})$$\frac{1}{4}$$\frac{1}{8}$8$\frac{1}{64}$Correct Option: , 2 Solution: $\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightleftharpoons 2 \mathrm{NH}_{3} \...
Read More →The number of chiral carbons present in sucrose is
Question: The number of chiral carbons present in sucrose is Solution: Total no. of chiral carbon in sucrose $=9$...
Read More →The major product formed in the following reaction is :
Question: The major product formed in the following reaction is : $\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHCH}\left(\mathrm{CH}_{3}\right)_{2} \stackrel{\mathrm{HBr}}{\longrightarrow}$$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{C}(\mathrm{Br})\left(\mathrm{CH}_{3}\right)_{2}$$\mathrm{Br}\left(\mathrm{CH}_{2}\right)_{3} \mathrm{CH}\left(\mathrm{CH}_{3}\right)_{2}$$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}(\mathrm{Br}) \mathrm{CH}\left(\mathrm{CH}_{3}\right)_{2}$$\mathrm{CH}_{3} \math...
Read More →Adsorption of a gas follows Freundlich adsorption isotherm. If x is the mass of the gas
Question: Adsorption of a gas follows Freundlich adsorption isotherm. If $x$ is the mass of the gas adsorbed on mass $\mathrm{m}$ of the adsorbent, the correct plot of $\frac{x}{m}$ versus $p$ is : Correct Option: , 3 Solution:...
Read More →Potassium chlorate is prepared by the electrolysis of
Question: Potassium chlorate is prepared by the electrolysis of $\mathrm{KCl}$ in basic solution $6 \mathrm{OH}^{-}+\mathrm{Cl}^{-} \rightarrow \mathrm{ClO}_{3}^{-}+3 \mathrm{H}_{2} \mathrm{O}+6 \mathrm{e}^{-}$ If only $60 \%$ of the current is utilized in the reaction, the time (rounded to the nearest hour) required to produce $10 \mathrm{~g}$ of $\mathrm{KCIO}_{3}$ using a current of $2 \mathrm{~A}$ is_____. (Given : $\mathrm{F}=96,500 \mathrm{C} \mathrm{mol}^{-1}$ molar mass of $\left.\mathrm...
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