Solve the following
Question: The correct order of stability of given carbocation is :$\mathrm{A}\mathrm{C}\mathrm{B}\mathrm{D}$$\mathrm{D}\mathrm{B}\mathrm{C}\mathrm{A}$$\mathrm{D}\mathrm{B}\mathrm{A}\mathrm{C}$$\mathrm{C}\mathrm{A}\mathrm{D}\mathrm{B}$Correct Option: 1 Solution:...
Read More →Number of electrons
Question: Number of electrons that Vanadium $(Z=23)$ has in p-orbitals is equal to__________. Solution: ${ }_{23} \mathrm{~V}: 1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{6} 3 \mathrm{~s}^{2} 3 \mathrm{p}^{6} 3 \mathrm{~d}^{3} 4 \mathrm{~s}^{2}$ Number of electrons in $\mathrm{p}$-orbitals is equal to $12.00$...
Read More →A copper complex crystallising
Question: A copper complex crystallising in a CCP lattice with a cell edge of $0.4518 \mathrm{~nm}$ has been revealed by employing X-ray diffraction studies. The density of a copper complex is found to be $7.62 \mathrm{~g} \mathrm{~cm}^{-3}$. The molar mass of copper complex is ________ $g \mathrm{~mol}^{-1}$ (Nearest integer) [Given : $\mathrm{N}_{\mathrm{A}}=6.022 \times 10^{23} \mathrm{~mol}^{-1}$ ] Solution: $\mathrm{d}\left(\frac{\mathrm{gm}}{\mathrm{cc}}\right)=\frac{4 \times \frac{\mathrm...
Read More →Match List - I with List - II :
Question: Match List - I with List - II : Choose the most appropriate answer from the options given below(a)-(ii), (b)-(ii), (c)-(iii), (d)-(ii), (e)-(iii)(a)-(ii), (b)-(iii), (c)-(ii), (d)-(i), (e)-(iii)(a)-(ii), (b)-(ii), (c)-(iii), (d)-(i), (e)-(iii)(a)-(ii), (b)-(i), (c)-(ii), (d)-(iii), (e)-(iii)Correct Option: , 2 Solution: $\mathrm{NaOH} \rightarrow$ Basic $\mathrm{Be}(\mathrm{OH})_{2} \rightarrow$ Amphoteric $\mathrm{Ca}(\mathrm{OH})_{2} \rightarrow$ Basic $\mathrm{B}(\mathrm{OH})_{3} \r...
Read More →The nature of oxides
Question: The nature of oxides $\mathrm{V}_{2} \mathrm{O}_{3}$ and $\mathrm{CrO}$ is indexed as 'X' and 'Y' type respectively. The correct set of X and $\mathrm{Y}$ is: Correct Option: , 4 Solution: $\mathrm{V}_{2} \mathrm{O}_{3}$ basic $\mathrm{CrO}$ basic...
Read More →The number of water molecules in gypsum, dead burnt plaster and plaster of paris, respectively are:
Question: The number of water molecules in gypsum, dead burnt plaster and plaster of paris, respectively are:2, 0 and 10.5, 0 and 25, 0 and 0.52, 0 and 0.5Correct Option: , 4 Solution:...
Read More →Given below are two statements: one is labelled as
Question: Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : Metallic character decreases and non-metallic character increases on moving from left to right in a period. Reason $(\mathbf{R}):$ It is due to increase in ionisation enthalpy and decrease in electron gain enthalpy, when one moves from left to right in a period. In the light of the above statements, choose the most appropriate answer from the options given below: (A...
Read More →If the standard molar enthalpy
Question: If the standard molar enthalpy change for combustion of graphite powder is $-2.48 \times 10^{2} \mathrm{~kJ} \mathrm{~mol}^{-1}$, the amount of heat generated on combustion of $1 \mathrm{~g}$ of graphite powder is __________ kJ. (Nearest integer) Solution: 1 mol graphite $=12 \mathrm{gm} \mathrm{C}$ Ans. $=\frac{248}{12}=20.67 \mathrm{~kJ} / \mathrm{gm}$ heat evolved...
Read More →Staggered and eclipsed conformers of ethane are :
Question: Staggered and eclipsed conformers of ethane are :PolymersRotamersEnantiomersMirror imagesCorrect Option: , 2 Solution: Staggered and eclipsed conformers of ethane also known as rotamers...
Read More →The gas 'A' is having very low reactivity reaches to stratosphere. I
Question: The gas 'A' is having very low reactivity reaches to stratosphere. It is nontoxic and nonflammable but dissociated by UVradiations in stratosphere. The intermediates formed initially from the gas 'A' are :Correct Option: , 4 Solution: In stratosphere CFCs get broken down by powerful UV radiations releasing$\mathrm{Cl}^{*}$ $\mathrm{CF}_{2} \mathrm{Cl}_{2}(\mathrm{~g}) \stackrel{\mathrm{U} \cdot \mathrm{v}}{\longrightarrow} \mathrm{Cl}^{*}(\mathrm{~g})+{ }^{*} \mathrm{CF}_{2} \mathrm{Cl...
Read More →Value of
Question: Value of $K_{P}$ for the equilibrium reaction $\mathrm{N}_{2} \mathrm{O}_{4}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}_{2(\mathrm{~g})}$ at $288 \mathrm{~K}$ is $47.9 .$ The $\mathrm{K}_{\mathrm{C}}$ for this reaction at same temperature is _________. (Nearest integer) $\left(\mathrm{R}=0.083 \mathrm{~L}\right.$ bar $\left.\mathrm{K}^{-1} \mathrm{~mol}^{-1}\right)$ Solution: $\mathrm{K}_{\mathrm{C}}=\frac{\mathrm{K}_{\mathrm{P}}}{\mathrm{RT}}=\frac{47.9}{0.083 \times 288}=2$...
Read More →The denticity of an organic ligand, biuret is :
Question: The denticity of an organic ligand, biuret is :2436Correct Option: 1 Solution: Biuret :- Bidentate ligand The denticity of organic ligand is 2 ....
Read More →Prove the following
Question: The compound 'A' is a complementary base of_______ in DNA stands.UracilGuanineAdenineCytosineCorrect Option: , 3 Solution: Given structure is Thymine and Thymine being paired with adenine...
Read More →Assume a cell with the following reaction
Question: Assume a cell with the following reaction $\mathrm{Cu}_{(\mathrm{s})}+2 \mathrm{Ag}^{+}\left(1 \times 10^{-3} \mathrm{M}\right) \rightarrow \mathrm{Cu}^{2+}(0.250 \mathrm{M})+2 \mathrm{Ag}_{(\mathrm{s})}$ $\mathrm{E}_{\text {cell }}^{\ominus}=2.97 \mathrm{~V}$ $\mathrm{E}_{\text {cell for the above reaction is }}$_____________ V. (Nearest integer) [Given : $\log 2.5=0.3979, \mathrm{~T}=298 \mathrm{~K}$ ] Solution: $\mathrm{E}=\mathrm{E}^{\circ}-\frac{0.059}{2} \log \frac{\left[\mathrm{...
Read More →Given below are two statements: one is labelled as
Question: Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : Treatment of bromine water with propene yields 1-bromopropan-2-ol. Reason (R) : Attack of water on bromonium ion follows Markovnikov rule and results in 1 -bromopropan-2-ol. In the light of the above statements, choose the most appropriate answer from the options given below: Both (A) and (R) are true but (R) is NOT the correct explanation of (A)(A) is false but (R...
Read More →The number of acyclic
Question: The number of acyclic structural isomers (including geometrical isomers) for pentene are Solution:...
Read More →Acidic ferric chloride solution on treatment with excess of potassium ferrocyanide gives a Prussian blue coloured colloidal species. It is :
Question: Acidic ferric chloride solution on treatment with excess of potassium ferrocyanide gives a Prussian blue coloured colloidal species. It is :$\mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}$$\mathrm{K}_{5} \mathrm{Fe}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{2}$$\mathrm{HFe}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]$$\mathrm{KFe}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]$Correct Option: , 4 Solution:...
Read More →Methylation of
Question: Methylation of $10 \mathrm{~g}$ of benzene gave $9.2 \mathrm{~g}$ of toluene. Calculate the percentage yield of toluene - (Nearest integer) Solution: $\frac{\mathrm{A}_{\mathrm{y}}}{\mathrm{T}_{\mathrm{y}}}=\%$ yield $=\frac{9.2}{920} \times 78 \times 100 \Rightarrow 78 \%$...
Read More →The total number of unpaired
Question: The total number of unpaired electrons present in $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{2}$ and $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}$ is Solution: ${\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{2} }$ $\mathrm{Co}^{2+}:[\mathrm{Ar}] 3 \mathrm{~d}^{7} 4 \mathrm{~s}^{0} 4 \mathrm{p}^{0}$ For this complex $\Delta_{0}$ P.E., so pairing of electron does not take place. $\mathrm{sp}^{3} \mathrm{~d}^...
Read More →Which one of the following
Question: Which one of the following $0.06 \mathrm{M}$ aqueous solutions has lowest freezing point ?$\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}$$\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}$KI$\mathrm{K}_{2} \mathrm{SO}_{4}$Correct Option: 1 Solution: $\mathrm{T}_{\mathrm{f}}-\mathrm{T}_{\mathrm{f}}^{\prime}=\mathrm{i} \mathrm{K}_{\mathrm{f}} \cdot \mathrm{m}$ For minimum $\mathrm{T}_{\mathrm{f}}^{\prime}$ 'i' should be maximum. $\begin{array}{ll}\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)...
Read More →Given below are two statements :
Question: Given below are two statements : Statement-I : The process of producing syn-gas is called gasification of coal. Statement-II : The composition of syn-gas is $\mathrm{CO}+\mathrm{CO}_{2}+\mathrm{H}_{2}(1: 1: 1)$ In the light of the above statements, choose the most appropriate answer from the options given below:Statement-I is false but Statement-II is trueStatement-I is true but Statement-II is falseBoth Statement-I and Statement-II are falseBoth Statement-I and Statement-II are trueCo...
Read More →Which one of the following reactions
Question: Which one of the following reactions does not occur?Correct Option: , 3 Solution: (1) Aniline is lewis base give acid base reaction with $\mathrm{AlCl}_{3}$ and form Anilinium ion (2) Anilinium ion has strongest deactivated ring so further Friedel craft Alkylation not occurs....
Read More →Monomer of Novolac is:
Question: Monomer of Novolac is:3-Hydroxybutanoic acidphenol and melamineo-Hydroxymethylphenol1,3 -Butadiene and styreneCorrect Option: , 3 Solution: Monomer of Novolac is. O-hydroxy methyl phenol...
Read More →Which of the following is not a correct statement for primary aliphatic amines?
Question: Which of the following is not a correct statement for primary aliphatic amines?The intermolecular association in primary amines is less than the intermolecular association in secondary amines.Primary amines on treating with nitrous acid solution form corresponding alcohols except methyl amine.Primary amines are less basic than the secondary amines.Primary amines can be prepared by the Gabriel phthalimide synthesis.Correct Option: 1, Solution: The intermolecular association is more prom...
Read More →An organic compound
Question: An organic compound $\mathrm{A}\left(\mathrm{C}_{6} \mathrm{H}_{6} \mathrm{O}\right)$ gives dark green colouration with ferric chloride. On treatment with $\mathrm{CHCl}_{3}$ and $\mathrm{KOH}$, followed by acidification gives compound B. Compound B can also be obtained from compound $\mathrm{C}$ on reaction with pyridinium chlorochromate $(\mathrm{PCC}) .$ Identify $\mathrm{A}, \mathrm{B}$ and $\mathrm{C}$.Correct Option: 1 Solution:...
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