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Previous Years AIEEE/JEE Mains Questions
Q. If the roots of the equation $b x^{2}+c x+a=0$ be imaginary, then for all real values of x, the expression $3 b^{2} x^{2}+6 b c x+2 c^{2}$ is :-
(1) Greater than –4ab (2) Less than –4ab (3) Greater than 4ab (4) Less than 4ab
[AIEEE-2010]
Ans. (1)
since the roots of $\mathrm{bx}^{2}+\mathrm{cx}+\mathrm{a}=0$ are imaginary
$\because c^{2}-4 a b<0 \Rightarrow c^{2}<4 a b$
for exp. $3 b^{2} x^{2}+6 b c x+2 c^{2}$
Min. value $=\frac{-\mathrm{D}}{4 \mathrm{a}}=\frac{\left(36 \mathrm{b}^{2} \mathrm{c}^{2}-24 \mathrm{b}^{2} \mathrm{c}^{2}\right)}{12 \mathrm{b}^{2}}=\frac{-12 \mathrm{b}^{2} \mathrm{c}^{2}}{12 \mathrm{b}^{2}}=-\mathrm{c}^{2}$
$\therefore-\mathrm{c}^{2}>-4 \mathrm{ab}$
So exp. is greater than (– 4ab)
Q. If $\alpha$ and $\beta$ are the roots of the equation $x^{2}-x+1=0,$ then $\alpha^{2009}+\beta^{2009}=$
(1) –2 (2) –1 (3) 1 (4) 2
[AIEEE-2010]
Ans. (3)
Roots of equation $\mathrm{x}^{2}-\mathrm{x}+1=0 \mathrm{ar}$
$\alpha=-\omega, \quad \beta=-\omega^{2}$
$\alpha^{2009}+\beta^{2009}=(-\omega)^{2009}+\left(-\omega^{2}\right)^{2009}$c
$=-\left(\omega^{2}+\omega\right)=1$
Q. Let for $a \neq a_{1} \neq 0, f(x)=a x^{2}+b x+c, g(x)=a_{1} x^{2}+b_{1} x+c_{1}$ and $p(x)=f(x)-g(x)$
If $\mathrm{p}(\mathrm{x})=0$ only for $\mathrm{x}=-1$ and $\mathrm{p}(-2)=2,$ then the value of $\mathrm{p}(2)$ is:
(1) 18 (2) 3 (3) 9 (4) 6
[AIEEE-2011]
Ans. (1)
$\mathrm{P}(\mathrm{x})=\mathrm{k}(\mathrm{x}+1)^{2}$
$\mathrm{P}(-2)=2=\mathrm{k}(-1)^{2}$
$\Rightarrow \mathrm{k}=2$
$\therefore \mathrm{P}(\mathrm{x})=2(\mathrm{x}+1)^{2}$
$\Rightarrow \mathrm{P}(2)=18$
Aliter :
$\mathrm{P}(\mathrm{x})=\left(\mathrm{a}-\mathrm{a}_{1}\right) \mathrm{x}^{2}+\left(\mathrm{b}-\mathrm{b}_{1}\right) \mathrm{x}+\left(\mathrm{c}-\mathrm{c}_{1}\right)=0$
only x = –1
P(x) = 0
So roots are equal.
it means D = 0
$\left(b-b_{1}\right)^{2}=4\left(a-a_{1}\right)\left(c-c_{1}\right) \Rightarrow q^{2}=4 p r$
Let
$\mathrm{a}-\mathrm{a}_{1}=\mathrm{p}$
$\mathrm{b}-\mathrm{b}_{1}=\mathrm{q}$
$\mathrm{c}-\mathrm{c}_{1}=\mathrm{r}$
P(–1) = 0
p – q + r = 0 ...... (1)
4p – 2q + r = 2 ..... (2)
4p + 2q + r = ?
4p + 2q + r = ?
$(p+r)^{2}-4 p r=0$
$(p-r)^{2}=0$ 
from eq. (1) q = 2r
So from eq. (2) 4r – 4r + r = 2
r = 2
So 4p + 2q + r = 4r + 4r + r = 9r = 18
from eq. (1) q = 2r
So from eq. (2) 4r – 4r + r = 2
r = 2
So 4p + 2q + r = 4r + 4r + r = 9r = 18
Q. Sachin and Rahul attempted to solve a quadratic equation. Sachin made a mistake in writing down the constant term and ended up in roots (4, 3). Rahul made a mistake in writing down coefficient of x to get roots (3, 2). The correct roots of equation are:
(1) –4, –3 (2) 6, 1 (3) 4, 3 (4) –6, –1
[AIEEE-2011]
Ans. (2)
Q. The equation $\mathrm{e}^{\mathrm{sinx}}-\mathrm{e}^{-\mathrm{sinx}}-4=0$ has :
(1) exactly four real roots.
(2) infinite number of real roots.
(3) no real roots.
(4) exactly one real root.
[AIEEE-2012]
Ans. (3)
Q. If the equations $\mathrm{x}^{2}+2 \mathrm{x}+3=0$ and $\mathrm{ax}^{2}+\mathrm{bx}+\mathrm{c}=0, \mathrm{a}, \mathrm{b}, \mathrm{c} \in \mathrm{R}$, have a common root, then a : b : c is :
(1) 1 : 2 : 3 (2) 3 : 2 : 1 (3) 1 : 3 : 2 (4) 3 : 1 : 2
[JEE-MAIN-2013]
Ans. (1)
$\mathrm{x}^{2}+2 \mathrm{x}+3=0$
$\mathrm{D}<0$
$\therefore \quad \mathrm{ax}^{2}+\mathrm{bx}+\mathrm{c}=0 \mathrm{has}$
both roots common
$\therefore \quad a: b: c=1: 2: 3$
Q. Let and $\beta$ be the roots of equation $\mathrm{x}^{2}-6 \mathrm{x}-2=0 .$ If $\mathrm{a}_{\mathrm{n}}=\alpha^{\mathrm{n}}-\beta^{\mathrm{n}},$ for $\mathrm{n} \geq$ 1, then the value of $\frac{\mathrm{a}_{10}-2 \mathrm{a}_{8}}{2 \mathrm{a}_{9}}$ is equal to :
(1) 3 (2) – 3 (3) 6 (4) – 6
[JEE-MAIN-2015]
Ans. (1)
Q. The sum of all real values of x satisfying the equation $\left(x^{2}-5 x+5\right)^{x^{2}+4 x-60}=1$ is :
(1) 5 (2) 3 (3) –4 (4) 6
[JEE-MAIN-2016]
Ans. (2)
$\mathrm{x}^{2}-5 \mathrm{x}+5=1 \Rightarrow \mathrm{x}=1,4$
$x^{2}-5 x+5=-1 \Rightarrow x=2,3$
but 3 is rejected
$\mathrm{x}^{2}+4 \mathrm{x}-60=0 \Rightarrow \mathrm{x}=-10,6$
Sum = 3
Q. If $\alpha, \beta \in \mathrm{C}$ are the distinct roots of the equation $\mathrm{x}^{2}-\mathrm{x}+1=0,$ then $\alpha^{101}+\beta^{107}$ is equal to-
If $\alpha, \beta \in \mathrm{C}$ are the distinct roots of the equation $\mathrm{x}^{2}-\mathrm{x}+1=0,$ then $\alpha^{101}+\beta^{107}$ is equal to-
[JEE-MAIN-2018]
Ans. (2)
