Y = A sin (ωt + Φ0) is the time-displacement equation

Question:

$\mathrm{Y}=\mathrm{A} \sin \left(\omega \mathrm{t}+\phi_{0}\right)$ is the time-displacement equation of a SHM. At $t=0$ the displacement

of the particle is $Y=\frac{A}{2}$ and it is moving along

negative $x$-direction. Then the initial phase angle $\phi_{0}$ will be :

  1. $\frac{\pi}{6}$

  2. $\frac{\pi}{3}$

  3. $\frac{5 \pi}{6}$

  4. $\frac{2 \pi}{3}$


Correct Option: , 3

Solution:

initial phase $\frac{\pi}{2}+\frac{\pi}{3}=\frac{5 \pi}{6}$

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