Question:
$\mathrm{Y}=\mathrm{A} \sin \left(\omega \mathrm{t}+\phi_{0}\right)$ is the time-displacement equation of a SHM. At $t=0$ the displacement
of the particle is $Y=\frac{A}{2}$ and it is moving along
negative $x$-direction. Then the initial phase angle $\phi_{0}$ will be :
Correct Option: , 3
Solution:
initial phase $\frac{\pi}{2}+\frac{\pi}{3}=\frac{5 \pi}{6}$
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