Question:
−(x − 3) + 4 < 5 − 2x
Solution:
$-(x-3)+4<5-2 x$
$\Rightarrow-x+3+4<5-2 x$
$\Rightarrow-x+7<5-2 x$
$\Rightarrow-x+2 x<5-7 \quad[$ Transposing $-2 \mathrm{x}$ to LHS and 7 to RHS $]$
$\Rightarrow x<-2$
Hence, the solution set of the given inequation is $(-\infty,-2)$.
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