Write two solutions of the form

(i) We are given, 5x - 2y = 10

Substituting x = 0 in the given equation, We get;

5× 0 - 2y = 10 - 2y = 10 - y = 10/2

y = - 5

Thus x = 0 and y = - 5 is the solution of 5x - 2y = 10

Substituting y = 0 in the given equation, we get 5x – 2 × 0 = 10

5x = 10

x = 10/5

x = 2

Thus x = 2 and y = 0 is a solution of 5x - 2y = 10

(ii) We are given, - 4x + 3y = 12

Substituting x = 0 in the given equation, we get;

- 4 × 0 + 3y = 12

3y = 12

y = 4

Thus x = 0 and y = 4 is a solution of the - 4x + 3y = 12

Substituting y = 0 in the given equation, we get;

- 4x + 3 × 0 = 12 – 4x = 12

x = -12/4

x = - 3

Thus x = - 3 and y = 0 is a solution of - 4x + 3y = 12

(iii) We are given, 2x + 3y = 24

Substituting x = 0 in the given equation, we get; 2 × 0 + 3y = 24

3y = 24

y = 24/3

y = 8

Thus x = 0 and y = 8 is a solution of 2x+ 3y = 24

Substituting y = 0 in the given equation, we get;

2x + 3 × 0 = 24

2x = 24

x = 24/2

x =12

Thus x = 12 and y = 0 is a solution of 2x + 3y = 24