Question:
Write the sum of the coefficients in the expansion of $\left(1-3 x+x^{2}\right)^{111}$.
Solution:
To find the sum of coefficients, we plug 1 for each variable then, we get the sum of coefficients of the given expression.
$\therefore$ Sum of coefficient $=\left(1-3 x+x^{2}\right)^{111}$
$=\left(1-3 \times 1+1^{2}\right)^{111}$
$=(1-3+1)^{111}$
$=(1-3+1)^{111}$
$=(-1)^{111}$
$=-1$
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