Write the least value of cos2 x + sec2 x.
We know:
cos x can take the minimum value of -1">−1-1.
$\cos ^{2} x+\sec ^{2} x$
$=\frac{\cos ^{4} x+1}{\cos ^{2} x}$
$=\frac{(-1)^{4}+1}{(-1)^{2}}$
= 2
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