Question:
Write the first five terms of the sequences whose $\mathrm{n}^{\text {th }}$ term is $a_{n}=2^{n}$
Solution:
$a_{n}=2^{n}$
Substituting n = 1, 2, 3, 4, 5, we obtain
$a_{1}=2^{1}=2$
$a_{2}=2^{2}=4$
$a_{3}=2^{3}=8$
$a_{4}=2^{4}=16$
$a_{5}=2^{5}=32$
Therefore, the required terms are $2,4,8,16$, and 32 .