Question:
Write the coefficient of the middle term in the expansion of $(1+x)^{2 n}$.
Solution:
Here, $n$, i. e., $2 n$, is an even number.
$\therefore$ Middle term $=\left(\frac{2 n}{2}+1\right)$ th term $=(n+1)$ th term
Thus, we have :
$T_{n+1}={ }^{2 n} C_{n}(1)^{2 n-n}(x)^{n}$
$={ }^{2 n} C_{n} x^{n}$
Hence, the coefficient of the middle term is ${ }^{2 n} C_{n}$