Question:
Write the additive inverse of each of the following rational numbers:
(i) $\frac{-2}{17}$
(ii) $\frac{3}{-11}$
(iii) $\frac{-17}{5}$
(iv) $\frac{-11}{-25}$
Solution:
(i) Additive inverse is the negative of the given number.
So, additive inverse of $\frac{-2}{17}$ is $\frac{2}{17}$.
(ii) Additive inverse is the negative of the given number.
So, additive inverse of $\frac{3}{-11}$ is $\frac{3}{11}$.
(iii) Additive inverse is the negative of the given number.
So, additive inverse of $\frac{-17}{5}$ is $\frac{17}{5}$.
(iv) Additive inverse is the negative of the given number.
So, additive inverse of $\frac{-11}{-25}$ is $\frac{-11}{25}$.