Question:
Write reactions of the final alkylation product of aniline with excess of methyliodide in the presence of sodium carbonate solution.
Solution:
Aniline reacts with methyl iodide to produce N, N-dimethylaniline.
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With excess methyl iodide, in the presence of Na2CO3 solution, N, N-dimethylaniline produces N, N, N−trimethylanilinium carbonate.
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