Which of the following is not a quadratic equation?
(a) 2 (x -1)2 = 4x2 – 2x +1
(b) 2x – x2 = x2 + 5
(c) (-√2X +√3)2 = 3x2 – 5x
(d) (x2 + 2x)2 = x4 + 3 + 4x2
(d)
(a) Given that, $2(x-1)^{2}=4 x^{2}-2 x+1$
$\Rightarrow \quad 2\left(x^{2}+1-2 x\right)=4 x^{2}-2 x+1$
$\Rightarrow \quad 2 x^{2}+2-4 x=4 x^{2}-2 x+1$
$\Rightarrow \quad 2 x^{2}+2 x-1=0$
which represents a quadratic equation because it has the quadratic form $a x^{2}+b x+c=0, a \neq 0$
(b) Given that, $2 x-x^{2}=x^{2}+5$
$\Rightarrow$ $2 x^{2}-2 x+5=0$
which also represents a quadratic equation because it has the quadratic form $a x^{2}+b x+c=0, a \neq 0$.
(c) Given that, $(\sqrt{2} \cdot x+\sqrt{3})^{2}=3 x^{2}-5 x$
$\Rightarrow \quad 2 \cdot x^{2}+3+2 \sqrt{6} \cdot x=3 x^{2}-5 x$
$\Rightarrow \quad x^{2}-(5+2 \sqrt{6}) x-3=0$
which also represents a quadratic equation because it has the quadratic form $a x^{2}+b x+c=0, a \neq 0$
(d) Given that, $\left(x^{2}+2 x\right)^{2}=x^{4}+3+4 x^{2}$
$\Rightarrow \quad x^{4}+4 x^{2}+4 x^{3}=x^{4}+3+4 x^{2}$
$\Rightarrow \quad 4 x^{3}-3=0$
which is not of the form $a x^{2}+b x+c, a \neq 0$. Thus, the equation is not quadratic. This is a cubic equation.