Question:
Which of the following equation depicts the oxidizing nature of $\mathrm{H}_{2} \mathrm{O}_{2}$ ?
Correct Option: , 3
Solution:
$2 \mathrm{l}^{-}+\mathrm{H}_{2} \mathrm{O}_{2}+2 \mathrm{H}^{+} \rightarrow \mathrm{I}_{2}+2 \mathrm{H}_{2} \mathrm{O}$
Oxygen reduces from $-1$ to $-2$ So, its reduction will takes place. Hence it will behave as oxidising agent or it shows oxidising nature. While in other option it change from $(-1)$ to 0 .