Which of the following cannot be true for a polyhedron?
(a) V = 4, F = 4, E = 6
(b) V=6,F=8,E=12
(c) V = 20,F = 12, E = 30
(d) V = 4, F = 6, E = 6
(d) We know that, Euler’s formula for any polyhedron isF+V-E = 2
where, F = faces, V = vertices
and E =edges
(a) $V=4, F=4$ and $E=6$
$\mathrm{LHS}=F+V-E$
$=4+4-6$
$=8-6=2$
$=\mathrm{RHS}$
$\therefore$ Option (a) is true for a polyhedron.
(b) $V=6, F=8$ and $E=12$
$\mathrm{LHS}=F+V-E$
$=8+6-12$
$=14-12=2$
$=\mathrm{RHS}$
$\therefore$ Option (b) is true for a polyhedron.
(c) $V=20, F=12$ and $E=30$
$\mathrm{LHS}=F+V-E$
$=12+20-30$
$=32-30=2$
$=\mathrm{RHS}$
$\therefore$ Option (c) is true for a polyhedron.
(d) $V=4, F=6$ and $E=6$
$\mathrm{LHS}=F+V-E$
$=6+4-6$
$=10-6=4 \neq R H S$
$\therefore$ Option (d) is not true for a polyhedron.