Question:
Which of the following are pairs of equal sets?
$J=\{2,3\}$ and $K=\left\{x: x \in Z,\left(x^{2}+5 x+6\right)=0\right\}$
Solution:
Equal Sets = Two sets A and B are said to be equal if they have exactly the
same elements & we write A = B
We have,
$J=\{2,3\}$
and $K=\left\{x: x \in Z,\left(x^{2}+5 x+6\right)=0\right\}$
Here, $x \in Z$ and $x^{2}+5 x+6=0$
The given equation can be solved as:
$x^{2}+5 x+6=0$
$\Rightarrow x^{2}+2 x+3 x+6=0$
$\Rightarrow x(x+2)+3(x+2)=0$
$\Rightarrow(x+2)(x+3)=0$
$\Rightarrow x=-2$ and $-3$
$\therefore K=\{-2,-3\}$
∴ J ≠ K because elements of both the sets are not equal.