Question:
When a die is thrown, the probability of getting an odd number less than 3 is ,
(a) $\frac{1}{6}$
(b) $\frac{1}{3}$
(c) $\frac{1}{2}$
(d) 0
Solution:
(a) When a die-is thrown, then total number of outcomes $=6$ Odd number less than 3 is 1 only. Number of possible outcomes $=1$
Required probability $=\frac{1}{6}$