What will be the minimum pressure required to compress 500 dm3

Given,

Initial pressure, p1 = 1 bar

Initial volume, V1 = 500 dm3

Final volume, V2 = 200 dm3

Since the temperature remains constant, the final pressure (p2) can be calculated using Boyle’s law.

According to Boyle’s law,

$p_{1} V_{1}=p_{2} V_{2}$

$\Rightarrow p_{2}=\frac{p_{1} V_{1}}{V_{2}}$

$=\frac{1 \times 500}{200} \mathrm{bar}$

$=2.5 \mathrm{bar}$

Therefore, the minimum pressure required is 2.5 bar.