Question:
What should be added to $\frac{-7}{8}$ so as to get $\frac{5}{9} ?$
Solution:
Let $x$ be added to $\frac{-7}{8}$ so as to get $\frac{5}{9}$.
$\therefore x+\frac{-7}{8}=\frac{5}{9}$
$\Rightarrow x=\frac{5}{9}-\frac{-7}{8}$
$\Rightarrow x=\frac{40}{72}-\frac{-63}{72}$
$\Rightarrow x=\frac{40-(-63)}{72}$
$\Rightarrow x=\frac{40+63}{72}=\frac{103}{72}$
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