Question:
What is $K_{c}$ for the following equilibrium when the equilibrium concentration of each substance is: $\left[\mathrm{SO}_{2}\right]=0.60 \mathrm{M},\left[\mathrm{O}_{2}\right]=0.82 \mathrm{M}$ and $\left[\mathrm{SO}_{3}\right]=1.90 \mathrm{M} ?$
$2 \mathrm{SO}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \longleftrightarrow 2 \mathrm{SO}_{3}(\mathrm{~g})$
Solution:
The equilibrium constant (Kc) for the give reaction is:
Hence, $K_{c}$ for the equilibrium is $12.239 \mathrm{M}^{-1}$.