What happens to the cube of a number if the number is multiplied by
(i) 3?
(ii) 4?
(iii) 5?
(i)
Let us consider a number $n$. Its cube would be $n^{3}$. If $n$ is multiplied by 3 , it becomes $3 n$.
Let us now find the cube of 3n, we get:
$(3 n)^{3}=3^{3} \times n^{3}=27 n^{3}$
Therefore, the cube of 3n is 27 times of the cube of n.
Thus, if a number is multiplied by 3, its cube is 27 times of the cube of that number.
(ii)
Let us consider a number $n$. Its cube would be $n^{3}$. If $n$ is multiplied by 4 , it becomes $4 n$.
Let us now find the cube of 4n, we get:
$(4 n)^{3}=4^{3} \times n^{3}=64 n^{3}$
Therefore, the cube of 4n is 64 times of the cube of n.
Thus, if a number is multiplied by 4, its cube is 64 times of the cube of that number.
(iii)
Let us consider a number $n$. Its cube would be $n^{3}$. If the number $n$ is multiplied by 5 , it becomes $5 n$.
Let us now find the cube of 4n, we get:
$(5 n)^{3}=5^{3} \times n^{3}=125 n^{3}$
Therefore, the cube of 5n is 125 times of the cube of n.
Thus, if a number is multiplied by 5, its cube is 125 times of the cube of that number.