Question: Water does not produce $\mathrm{CO}$ on reacting with :
$\mathrm{C}_{3} \mathrm{H}_{8}$
C
$\mathrm{CH}_{4}$
$\mathrm{CO}_{2}$
Correct Option: , 4
Solution:
$\mathrm{H}_{2} \mathrm{O}+\mathrm{CO}_{2} \rightarrow \mathrm{H}_{2} \mathrm{CO}_{3}$
