Question:
Very-Short-Answer Questions
Show that $x=-2$ is a solution of $3 x^{2}+13 x+14=0$.
Solution:
The given equation is $3 x^{2}+13 x+14=0$.
Putting x = −2 in the given equation, we get
$\mathrm{LHS}=3 \times(-2)^{2}+13 \times(-2)+14=12-26+14=0=\mathrm{RHS}$
∴ x = −2 is a solution of the given equation.