Question:
Very-Short and Short-Answer Questions
If k, (2k − 1) and (2k + 1) are the three successive terms of an AP, find the value of k.
Solution:
It is given that k, (2k − 1) and (2k + 1) are the three successive terms of an AP.
$\therefore(2 k-1)-k=(2 k+1)-(2 k-1)$
$\Rightarrow k-1=2$
$\Rightarrow k=3$
Hence, the value of k is 3.
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