Using square root table, find the square root

Using the table to find $\sqrt{2}$ and $\sqrt{41}$

$\sqrt{1312}=\sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 41}$

$=2 \times 2 \sqrt{2} \times \sqrt{41}$

$=2 \times 2 \times 1.414 \times 6.4031$

$=36.222$