Using remainder theorem, find the remainder when $p(x)=x^{3}+3 x^{2}-5 x+4$ is divided by $(x-2)$.
Given : $p(x)=x^{3}+3 x^{2}-5 x+4$
Now, $p(2)=2^{3}+3\left(2^{2}\right)-5(2)+4$
$=8+12-10+4$
$=14$
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