Using prime factorisation,

Question:

Using prime factorisation, find the square roots of (a) 11025 (b) 4761

Solution:

(a) We have, 11025

Now, $\quad 11025=3 \times 3 \times 5 \times 5 \times 7 \times 7$

$\therefore$ Square root of $11025=\sqrt{11025}=3 \times 5 \times 7=105$

(b) We have, 4761

Now, $4761=3 \times 3 \times 23 \times 23$

$\therefore$ Square root of $4761=\sqrt{4761}=3 \times 23=69$

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