Question:
Using prime factorisation, find the square roots of (a) 11025 (b) 4761
Solution:
(a) We have, 11025
Now, $\quad 11025=3 \times 3 \times 5 \times 5 \times 7 \times 7$
$\therefore$ Square root of $11025=\sqrt{11025}=3 \times 5 \times 7=105$
(b) We have, 4761
Now, $4761=3 \times 3 \times 23 \times 23$
$\therefore$ Square root of $4761=\sqrt{4761}=3 \times 23=69$
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