Question:
Two triangles ABC and PQR are such that AB = 3 cm, AC = 6 cm, ∠A = 700 PR = 9 cm, ∠P = 700 and PQ = 4.5 cm. Show that
△ABC ∼ △PQR and state similarity theorem.
Solution:
Now, In △ABC and △PQR
∠A = ∠P = 700 (Given)
$\frac{\mathrm{AB}}{\mathrm{PQ}}=\frac{\mathrm{AC}}{\mathrm{PR}} \quad\left[\because \frac{3}{4.5}=\frac{6}{9} \Rightarrow \frac{1}{1.5}=\frac{1}{1.5}\right]$
By SAS similarity criterion, △ABC ∼ △PQR