Question: Two particles of equal mass ' $m$ ' go around a circle of radius $\mathrm{R}$ under the action of their mutual gravitational attraction. The speed of each particle with respect to their centre of mass is:-
$\sqrt{\frac{\mathrm{Gm}}{\mathrm{R}}}$
$\sqrt{\frac{G m}{4 R}}$
$\sqrt{\frac{\mathrm{Gm}}{3 \mathrm{R}}}$
$\sqrt{\frac{\mathrm{Gm}}{2 \mathrm{R}}}$
Correct Option: , 3
Solution:
