Two numbers are in the ratio 5 : 6. If 8 is subtracted from each of the numbers, the ratio becomes 4 : 5, then find the numbers. .
Let the two numbers be x and y.
Then, by first Condition, ratio of these two numbers = 5:6
$x: y=5: 6$
$\Rightarrow$ $\frac{x}{y}=\frac{5}{6} \Rightarrow y=\frac{6 x}{5}$ $\ldots$ (i)
and by second condition, then, 8 is subtracted from each of the numbers, then ratio becomes $4: 5$.
$\frac{x-8}{y-8}=\frac{4}{5}$
$\Rightarrow \quad 5 x-40=4 y-32$
$\Rightarrow \quad 5 x-4 y=8$ ...(ii)
Now, put the value of $y$ in Eq. (ii), we get
$5 x-4\left(\frac{6 x}{5}\right)=8$
$\Rightarrow \quad 25 x-24 x=40$
$\Rightarrow \quad x=40$
Put the value of $x$ in Eq. (i), we get
$y=\frac{6}{5} \times 40$
$=6 \times 8=48$
Hence, the required numbers are 40 and 48.