Two cubes each of volume 125 cm3 are joined end to end to form a solid.

Solution:

Let the edge of the cube be $a$.

As,

Volume of the cube $=125 \mathrm{~cm}^{3}$

$\Rightarrow a^{3}=125$

$\Rightarrow a=\sqrt[3]{125}$

$\Rightarrow a=5 \mathrm{~cm}$

So,

Length of the resulting cuboid, $l=2 \times 5=10 \mathrm{~cm}$,

Breadth of the resulting cuboid, $b=5 \mathrm{~cm}$ and

Height of the resulting cuboid, $h=5 \mathrm{~cm}$

Now,

Surface area of the resulting cuboid $=2(l b+b h+h l)$

$=2 \times(10 \times 5+5 \times 5+5 \times 10)$

$=2 \times(50+25+50)$

$=2 \times 125$

$=250 \mathrm{~cm}^{2}$

So, the surface area of the resulting cuboid is 250 cm2.