Top surface of a table is trapezium in shape.

The given figure is:

Lengths of the parallel sides are $1.2 \mathrm{~m}$ and $1 \mathrm{~m}$ and the perpendicular distance between them is $0.8 \mathrm{~m}$.

$\therefore$ Area of the trapezium shaped surface $=\frac{1}{2} \times($ Sum of the parallel sides $) \times($ Perpendicular distance $)$

$=\frac{1}{2} \times(1.2+1) \times(0.8)$

$=\frac{1}{2} \times 2.2 \times 0.8$

$=0.88 \mathrm{~m}^{2}$