Question:
To construct a triangle similar to a given $\triangle A B C$ with its sides $\frac{8}{5}$ of the corresponding sides of $\triangle A B C$ draw a ray $B X$
such that $\angle C B X$ is an acute angle and $X$ is on the opposite side of $A$ with respect to $B C$. The minimum number of points to be located
at equal distances on ray BX is
(a) 5
(b) 8
(c) 13
(d) 3
Solution:
(b) To construct a triangle similar to a given triangle, with its sides $\frac{m}{n}$ of the corresponding sides of given triangle the minimum number of points to be located at equal distance is equal to the greater of $m$ and $n$ is $\frac{8}{5}$
Hence, $\frac{m}{n}=\frac{8}{5}$
So, the minimum number of point to be located at equal distance on ray BX is 8 .