To construct a triangle similar to a given

Question:

To construct a triangle similar to a given $\triangle \mathrm{ABC}$ with its sides $\frac{3}{7}$ of the corresponding sides of $\triangle \mathrm{ABC}$,

first draw a ray $B X$ such that $\angle C B X$ is an acute angle and $X$ lies on the opposite side of $A$ with respect to $B C$. Then, locate points

$B_{1}, B_{2}, B_{3} \ldots$ on $B X$ at equal distances and next step is to join

(a) B 10 to C

(b) $B_{13}$ to $C$

(c) $B_{7}$ to $C$

(d) $B_{4}$ to $C$

Solution:

(c) Here, we locate points B1, B2, B3, B4, B5, B6 and B7 on BX at equal distance and in next step join the last points is B7 to C.

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