Tick (✓) the correct answer
$\left(\frac{-3}{4}\right)^{2}=?$
(a) $\frac{-9}{16}$
(b) $\frac{9}{16}$
(c) $\frac{16}{9}$
(d) $\frac{-16}{9}$
$\left(\frac{-3}{4}\right)^{2}=\frac{(-3)^{2}}{(4)^{2}}=\frac{9}{16}$
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