Question:
Tick (✓) the correct answer
The product of two numbers is $\frac{-16}{35}$. If one of the numbers is $\frac{-15}{14}$, the other is
(a) $\frac{-2}{5}$
(b) $\frac{8}{15}$
(C) $\frac{32}{75}$
(d) $\frac{-8}{3}$
Solution:
(C) $\frac{32}{75}$
Let the other number be x.
Now,
$x \times \frac{-15}{4}=\frac{-16}{35}$
$\Rightarrow x=\frac{-16}{35} \div \frac{-15}{14}$
$=\frac{-16}{35} \times \frac{14}{-15}$
$=\frac{-(16 \times 14)}{-(35 \times 15)}$
$=\frac{16 \times 14}{35 \times 15}=\frac{224}{525}=\frac{32}{75}$
Thus, the other number is $\frac{32}{75}$