Question:
Tick (✓) the correct answer
$\left(\frac{31}{-4}+\frac{-5}{8}\right)=?$
(a) $\frac{67}{8}$
(b) $\frac{57}{8}$
(c) $\frac{-57}{8}$
(d) $\frac{-67}{8}$
Solution:
(d) $\frac{-67}{8}$
$\frac{31}{-4}=\frac{-31}{4}$
We have:
$\left(\frac{31}{-4}+\frac{-5}{8}\right)=\left(\frac{-31}{4}+\frac{-5}{8}\right)$
LCM of 4 and 8 is 8 , that is, $(4 \times 1 \times 2)$.
$\left(\frac{-31}{4}+\frac{-5}{8}\right)=\frac{2 \times(-31)+1 \times(-5)}{8}$
$=\frac{(-62)+(-5)}{8}$
$=\frac{-67}{8}$