Question:
Tick (✓) the correct answer
If 64y8 is exactly divisible by 3, then the least value of y is
(a) 0
(b) 1
(c) 2
(d) 3
Solution:
(a) 0
If a number is divisible by 3, then the sum of the digits is also divisible by 3.
$6+4+y+8=18+y$
This is divisible by 3 as $y$ is equal to 0 .