Tick (✓) the correct answer

Question:

Tick (✓) the correct answer

$\left[\left\{\left(-\frac{1}{2}\right)^{2}\right\}^{-2}\right]^{-1}=?$

(a) $\frac{1}{16}$

(b) 16

(c) $-\frac{1}{16}$

(d) $-16$

Solution:

(a) $\frac{1}{16}$

$\left[\left\{\left(-\frac{1}{2}\right)^{2}\right\}^{-2}\right]^{-1}$

$=\left[\left\{-\frac{1}{2}\right\}^{-4}\right]^{-1}$

$=\left(-\frac{1}{2}\right)^{(-4 \times-1)}$

$=\left(-\frac{1}{2}\right)^{4}$

$=\frac{1}{16}$

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