Question:
Tick (✓) the correct answer:
Sum of three consecutive integers is 51. The middle one is
(a) 14
(b) 15
(c) 16
(d) 17
Solution:
(d) 17
Let the three consecutive integers be $x, x+1$ and $x+2$.
Equation $=x+x+1+x+2=51$
$\Rightarrow 3 x+3=51$
$\Rightarrow 3 x=51-3$
$\Rightarrow 3 x=48$
$\Rightarrow x=\frac{48}{3}=16$
Middle integer $=x+1=16+1=17$