Tick (✓) the correct answer

Question:

Tick (✓) the correct answer

$\left(\frac{1}{2}\right)^{-2}+\left(\frac{1}{3}\right)^{-2}+\left(\frac{1}{4}\right)^{-2}=?$

(a) $\frac{61}{144}$

(b) $\frac{144}{61}$

(C) 29

(d) $\frac{1}{29}$

Solution:

(C) 29

$\left(\frac{1}{2}\right)^{-2}+\left(\frac{1}{3}\right)^{-2}+\left(\frac{1}{4}\right)^{-2}=\left(\frac{2}{1}\right)^{2}+\left(\frac{3}{1}\right)^{2}+\left(\frac{4}{1}\right)^{2}$

$=2^{2}+3^{2}+4^{2}$

$=4+9+16$

$=29$

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