Question:
Tick (✓) the correct answer:
A polygon has 27 diagonals. How many sides does it have?
(a) 7
(b) 8
(c) 9
(d) 12
Solution:
(c) 9
$\frac{n(n-3)}{2}=27$
$\Rightarrow n(n-3)=54$
$\Rightarrow n^{2}-3 n-54=0$
$\Rightarrow n^{2}-9 n+6 n-54=0$
$\Rightarrow n(n-9)+6(n-9)=0$
$\Rightarrow n=-6$ or $n=9$
Number of sides cannot be negative.
$\therefore \mathrm{n}=9$