Tick (✓) the correct answer

Question:

Tick (✓) the correct answer

$\left(2^{-5} \div 2^{-2}\right)=?$

(a) $\frac{1}{128}$

(b) $\frac{-1}{128}$

(c) $-\frac{1}{8}$

(d) $\frac{1}{8}$

Solution:

(d) $\frac{1}{8}$

$\left(2^{-5} \div 2^{-2}\right)=\left(\frac{1}{2^{5}} \div \frac{1}{2^{2}}\right)=\left(\frac{1}{32} \div \frac{1}{4}\right)=\left(\frac{1}{32} \times 4\right)=\frac{4}{32}=\frac{1}{8}$

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