Question:
Three unbiased coins are tossed once. Find the probability of getting exactly one tail
Solution:
We know that
Probability of occurrence of an event
$=\frac{\text { Total no.of Desired outcomes }}{\text { Total no.of outcomes }}$
Let $\mathrm{T}$ be tails and $\mathrm{H}$ be heads
Total possible outcomes = TTT, TTH, THT, HTT, THH, HTH, HHT, HHH
Desired outcomes are exactly one tail. So, desired outputs are THH, HTH, HHT
Total no. of outcomes are 8 and desired outcomes are 3
Therefore, the probability of getting exactly one tail $=\frac{3}{8}$
Conclusion: Probability of getting exactly one tail is $\frac{3}{8}$
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